ee1e8abd87
* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
90 lines
1.9 KiB
Markdown
90 lines
1.9 KiB
Markdown
---
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id: 5a23c84252665b21eecc7eb0
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title: 我在E之前除了C之后
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challengeType: 5
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videoUrl: ''
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dashedName: i-before-e-except-after-c
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---
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# --description--
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短语[“我在E之前，除了C之后”](<https://en.wikipedia.org/wiki/I before E except after C>)是一个广为人知的助记符，它应该有助于拼写英语单词。使用提供的单词，检查短语的两个子句是否合理：
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1. *“我在E之前没有前面的C”。*
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2. *“在我之前的C之前是C”。*
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如果两个子短语都是合理的，则原始短语可以说是合理的。编写一个接受单词的函数，并检查单词是否遵循此规则。如果该函数遵循规则，则该函数应返回true，否则返回false。
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# --hints--
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`IBeforeExceptC`应该是一个函数。
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```js
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assert(typeof IBeforeExceptC == 'function');
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```
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`IBeforeExceptC("receive")`应该返回一个布尔值。
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```js
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assert(typeof IBeforeExceptC('receive') == 'boolean');
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```
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`IBeforeExceptC("receive")`应该返回`true` 。
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```js
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assert.equal(IBeforeExceptC('receive'), true);
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```
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`IBeforeExceptC("science")`应该返回`false` 。
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```js
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assert.equal(IBeforeExceptC('science'), false);
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```
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`IBeforeExceptC("imperceivable")`应该返回`true` 。
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```js
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assert.equal(IBeforeExceptC('imperceivable'), true);
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```
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`IBeforeExceptC("inconceivable")`应该返回`true` 。
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```js
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assert.equal(IBeforeExceptC('inconceivable'), true);
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```
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`IBeforeExceptC("insufficient")`应返回`false` 。
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```js
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assert.equal(IBeforeExceptC('insufficient'), false);
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```
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`IBeforeExceptC("omniscient")`应该返回`false` 。
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```js
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assert.equal(IBeforeExceptC('omniscient'), false);
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```
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# --seed--
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## --seed-contents--
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```js
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function IBeforeExceptC(word) {
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}
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```
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# --solutions--
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```js
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function IBeforeExceptC(word)
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{
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if(word.indexOf("c")==-1 && word.indexOf("ie")!=-1)
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return true;
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else if(word.indexOf("cei")!=-1)
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return true;
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return false;
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}
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```
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