ee1e8abd87
* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
1.5 KiB
1.5 KiB
id, title, challengeType, videoUrl, dashedName
| id | title | challengeType | videoUrl | dashedName |
|---|---|---|---|---|
| 5a23c84252665b21eecc7ec1 | 迭代的数字平方 | 5 | iterated-digits-squaring |
--description--
如果添加自然数（大于零的整数）的数字的平方，则始终以1或89结尾：
15 - > 26 - > 40 - > 16 - > 37 - > 58 - > 89
7 - > 49 - > 97 - > 130 - > 10 - > 1
编写一个函数，该函数将数字作为参数，并在执行上述过程后返回1或89。
--hints--
iteratedSquare应该是一个函数。
assert(typeof iteratedSquare == 'function');
iteratedSquare(4)应该返回一个数字。
assert(typeof iteratedSquare(4) == 'number');
iteratedSquare(4)应该返回89 。
assert.equal(iteratedSquare(4), 89);
iteratedSquare(7)应该返回1 。
assert.equal(iteratedSquare(7), 1);
iteratedSquare(15)应该返回89 。
assert.equal(iteratedSquare(15), 89);
iteratedSquare(20)应该返回89 。
assert.equal(iteratedSquare(20), 89);
iteratedSquare(70)应该返回1 。
assert.equal(iteratedSquare(70), 1);
iteratedSquare(100)应该返回1 。
assert.equal(iteratedSquare(100), 1);
--seed--
--seed-contents--
function iteratedSquare(n) {
}
--solutions--
function iteratedSquare(n) {
var total;
while (n != 89 && n != 1) {
total = 0;
while (n > 0) {
total += Math.pow(n % 10, 2);
n = Math.floor(n/10);
}
n = total;
}
return n;
}