Oliver Eyton-Williams ee1e8abd87
feat(curriculum): restore seed + solution to Chinese (#40683)
* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
2021-01-12 19:31:00 -07:00

1.9 KiB
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id, title, challengeType, videoUrl, dashedName
id title challengeType videoUrl dashedName
594810f028c0303b75339ad3 矢量点积 5 vector-dot-product

--description--

矢量被定义为具有三个维度由三个数字的有序集合表示XYZ

任务:

 Write a function that takes any numbers of vectors (arrays) as input and computes their dot product. 

您的函数应在无效输入(即不同长度的向量)上返回null

--hints--

dotProduct必须是一个函数

assert.equal(typeof dotProduct, 'function');

dotProduct必须返回null

assert.equal(dotProduct(), null);

dotProduct1][1必须返回1。

assert.equal(dotProduct([1], [1]), 1);

dotProduct1][1,2必须返回null。

assert.equal(dotProduct([1], [1, 2]), null);

dotProduct[1,3-5][4-2-1]必须返回3。

assert.equal(dotProduct([1, 3, -5], [4, -2, -1]), 3);

dotProduct(...nVectors)应该返回dotProduct(...nVectors)

assert.equal(
  dotProduct(
    [0, 1, 2, 3, 4],
    [0, 2, 4, 6, 8],
    [0, 3, 6, 9, 12],
    [0, 4, 8, 12, 16],
    [0, 5, 10, 15, 20]
  ),
  156000
);

--seed--

--seed-contents--

function dotProduct(...vectors) {

}

--solutions--

function dotProduct(...vectors) {
  if (!vectors || !vectors.length) {
    return null;
  }
  if (!vectors[0] || !vectors[0].length) {
    return null;
  }
  const vectorLen = vectors[0].length;
  const numVectors = vectors.length;

  // If all vectors not same length, return null
  for (let i = 0; i < numVectors; i++) {
    if (vectors[i].length !== vectorLen) {
      return null;  // return undefined
    }
  }

  let prod = 0;
  let sum = 0;
  let j = vectorLen;
  let i = numVectors;
  // Sum terms
  while (j--) {
    i = numVectors;
    prod = 1;

    while (i--) {
      prod *= vectors[i][j];
    }
    sum += prod;
  }
  return sum;
}