ee1e8abd87
* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
92 lines
1.3 KiB
Markdown
92 lines
1.3 KiB
Markdown
---
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id: 56533eb9ac21ba0edf2244b1
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title: Compound Assignment With Augmented Multiplication
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challengeType: 1
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videoUrl: 'https://scrimba.com/c/c83vrfa'
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forumTopicId: 16662
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dashedName: compound-assignment-with-augmented-multiplication
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---
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# --description--
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The `*=` operator multiplies a variable by a number.
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`myVar = myVar * 5;`
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will multiply `myVar` by `5`. This can be rewritten as:
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`myVar *= 5;`
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# --instructions--
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Convert the assignments for `a`, `b`, and `c` to use the `*=` operator.
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# --hints--
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`a` should equal `25`.
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```js
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assert(a === 25);
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```
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`b` should equal `36`.
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```js
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assert(b === 36);
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```
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`c` should equal `46`.
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```js
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assert(c === 46);
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```
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You should use the `*=` operator for each variable.
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```js
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assert(code.match(/\*=/g).length === 3);
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```
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You should not modify the code above the specified comment.
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```js
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assert(
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/var a = 5;/.test(code) &&
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/var b = 12;/.test(code) &&
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/var c = 4\.6;/.test(code)
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);
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```
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# --seed--
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## --after-user-code--
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```js
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(function(a,b,c){ return "a = " + a + ", b = " + b + ", c = " + c; })(a,b,c);
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```
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## --seed-contents--
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```js
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var a = 5;
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var b = 12;
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var c = 4.6;
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// Only change code below this line
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a = a * 5;
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b = 3 * b;
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c = c * 10;
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```
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# --solutions--
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```js
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var a = 5;
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var b = 12;
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var c = 4.6;
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a *= 5;
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b *= 3;
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c *= 10;
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```
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