ee1e8abd87
* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
90 lines
1.3 KiB
Markdown
90 lines
1.3 KiB
Markdown
---
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id: 56533eb9ac21ba0edf2244b0
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title: Compound Assignment With Augmented Subtraction
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challengeType: 1
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videoUrl: 'https://scrimba.com/c/c2Qv7AV'
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forumTopicId: 16660
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dashedName: compound-assignment-with-augmented-subtraction
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---
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# --description--
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Like the `+=` operator, `-=` subtracts a number from a variable.
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`myVar = myVar - 5;`
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will subtract `5` from `myVar`. This can be rewritten as:
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`myVar -= 5;`
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# --instructions--
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Convert the assignments for `a`, `b`, and `c` to use the `-=` operator.
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# --hints--
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`a` should equal `5`.
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```js
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assert(a === 5);
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```
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`b` should equal `-6`.
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```js
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assert(b === -6);
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```
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`c` should equal `2`.
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```js
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assert(c === 2);
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```
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You should use the `-=` operator for each variable.
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```js
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assert(code.match(/-=/g).length === 3);
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```
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You should not modify the code above the specified comment.
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```js
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assert(
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/var a = 11;/.test(code) && /var b = 9;/.test(code) && /var c = 3;/.test(code)
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);
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```
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# --seed--
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## --after-user-code--
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```js
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(function(a,b,c){ return "a = " + a + ", b = " + b + ", c = " + c; })(a,b,c);
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```
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## --seed-contents--
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```js
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var a = 11;
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var b = 9;
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var c = 3;
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// Only change code below this line
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a = a - 6;
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b = b - 15;
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c = c - 1;
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```
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# --solutions--
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```js
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var a = 11;
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var b = 9;
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var c = 3;
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a -= 6;
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b -= 15;
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c -= 1;
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```
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