Oliver Eyton-Williams ee1e8abd87

feat(curriculum): restore seed + solution to Chinese (#40683 )

* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>

2021-01-12 19:31:00 -07:00

3.0 KiB

Raw Blame History

id, title, challengeType, forumTopicId, dashedName

id	title	challengeType	forumTopicId	dashedName
587d8253367417b2b2512c6c	Perform a Union on Two Sets	1	301708	perform-a-union-on-two-sets

--description--

In this exercise we are going to perform a union on two sets of data. We will create a method on our Set data structure called union. This method should take another Set as an argument and return the union of the two sets, excluding any duplicate values.

For example, if setA = ['a','b','c'] and setB = ['a','b','d','e'], then the union of setA and setB is: setA.union(setB) = ['a', 'b', 'c', 'd', 'e'].

--hints--

Your Set class should have a union method.

assert(
  (function () {
    var test = new Set();
    return typeof test.union === 'function';
  })()
);

The union of ["a", "b", "c"] and ["c", "d"] should return ["a", "b", "c", "d"].

assert(
  (function () {
    var setA = new Set();
    var setB = new Set();
    setA.add('a');
    setA.add('b');
    setA.add('c');
    setB.add('c');
    setB.add('d');
    var unionSetAB = setA.union(setB);
    var final = unionSetAB.values();
    return (
      final.indexOf('a') !== -1 &&
      final.indexOf('b') !== -1 &&
      final.indexOf('c') !== -1 &&
      final.indexOf('d') !== -1 &&
      final.length === 4
    );
  })()
);

--seed--

--seed-contents--

class Set {
  constructor() {
    // This will hold the set
    this.dictionary = {};
    this.length = 0;
  }
  // This method will check for the presence of an element and return true or false
  has(element) {
    return this.dictionary[element] !== undefined;
  }
  // This method will return all the values in the set
  values() {
    return Object.keys(this.dictionary);
  }
  // This method will add an element to the set
  add(element) {
    if (!this.has(element)) {
      this.dictionary[element] = true;
      this.length++;
      return true;
    }

    return false;
  }
  // This method will remove an element from a set
  remove(element) {
    if (this.has(element)) {
      delete this.dictionary[element];
      this.length--;
      return true;
    }

    return false;
  }
  // This method will return the size of the set
  size() {
    return this.length;
  }
  // Only change code below this line

  // Only change code above this line
}

--solutions--

class Set {
  constructor() {
    this.dictionary = {};
    this.length = 0;
  }

  has(element) {
    return this.dictionary[element] !== undefined;
  }

  values() {
    return Object.keys(this.dictionary);
  }

  add(element) {
    if (!this.has(element)) {
      this.dictionary[element] = true;
      this.length++;
      return true;
    }

    return false;
  }

  remove(element) {
    if (this.has(element)) {
      delete this.dictionary[element];
      this.length--;
      return true;
    }

    return false;
  }

  size() {
    return this.length;
  }

  union(set) {
    const newSet = new Set();
    this.values().forEach(value => {
      newSet.add(value);
    })
    set.values().forEach(value => {
      newSet.add(value);
    })

    return newSet;
  }
}

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