* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
6.3 KiB
id, title, challengeType, forumTopicId, dashedName
id | title | challengeType | forumTopicId | dashedName |
---|---|---|---|---|
587d8258367417b2b2512c7f | Use Breadth First Search in a Binary Search Tree | 1 | 301718 | use-breadth-first-search-in-a-binary-search-tree |
--description--
Here we will introduce another tree traversal method: breadth-first search. In contrast to the depth-first search methods from the last challenge, breadth-first search explores all the nodes in a given level within a tree before continuing on to the next level. Typically, queues are utilized as helper data structures in the design of breadth-first search algorithms.
In this method, we start by adding the root node to a queue. Then we begin a loop where we dequeue the first item in the queue, add it to a new array, and then inspect both its child subtrees. If its children are not null, they are each enqueued. This process continues until the queue is empty.
--instructions--
Let's create a breadth-first search method in our tree called levelOrder
. This method should return an array containing the values of all the tree nodes, explored in a breadth-first manner. Be sure to return the values in the array, not the nodes themselves. A level should be traversed from left to right. Next, let's write a similar method called reverseLevelOrder
which performs the same search but in the reverse direction (right to left) at each level.
--hints--
The BinarySearchTree
data structure should exist.
assert(
(function () {
var test = false;
if (typeof BinarySearchTree !== 'undefined') {
test = new BinarySearchTree();
}
return typeof test == 'object';
})()
);
The binary search tree should have a method called levelOrder
.
assert(
(function () {
var test = false;
if (typeof BinarySearchTree !== 'undefined') {
test = new BinarySearchTree();
} else {
return false;
}
return typeof test.levelOrder == 'function';
})()
);
The binary search tree should have a method called reverseLevelOrder
.
assert(
(function () {
var test = false;
if (typeof BinarySearchTree !== 'undefined') {
test = new BinarySearchTree();
} else {
return false;
}
return typeof test.reverseLevelOrder == 'function';
})()
);
The levelOrder
method should return an array of the tree node values explored in level order.
assert(
(function () {
var test = false;
if (typeof BinarySearchTree !== 'undefined') {
test = new BinarySearchTree();
} else {
return false;
}
if (typeof test.levelOrder !== 'function') {
return false;
}
test.add(7);
test.add(1);
test.add(9);
test.add(0);
test.add(3);
test.add(8);
test.add(10);
test.add(2);
test.add(5);
test.add(4);
test.add(6);
return test.levelOrder().join('') == '719038102546';
})()
);
The reverseLevelOrder
method should return an array of the tree node values explored in reverse level order.
assert(
(function () {
var test = false;
if (typeof BinarySearchTree !== 'undefined') {
test = new BinarySearchTree();
} else {
return false;
}
if (typeof test.reverseLevelOrder !== 'function') {
return false;
}
test.add(7);
test.add(1);
test.add(9);
test.add(0);
test.add(3);
test.add(8);
test.add(10);
test.add(2);
test.add(5);
test.add(4);
test.add(6);
return test.reverseLevelOrder().join('') == '791108305264';
})()
);
The levelOrder
method should return null
for an empty tree.
assert(
(function () {
var test = false;
if (typeof BinarySearchTree !== 'undefined') {
test = new BinarySearchTree();
} else {
return false;
}
if (typeof test.levelOrder !== 'function') {
return false;
}
return test.levelOrder() == null;
})()
);
The reverseLevelOrder
method should return null
for an empty tree.
assert(
(function () {
var test = false;
if (typeof BinarySearchTree !== 'undefined') {
test = new BinarySearchTree();
} else {
return false;
}
if (typeof test.reverseLevelOrder !== 'function') {
return false;
}
return test.reverseLevelOrder() == null;
})()
);
--seed--
--after-user-code--
BinarySearchTree.prototype = Object.assign(
BinarySearchTree.prototype,
{
add: function(value) {
function searchTree(node) {
if (value < node.value) {
if (node.left == null) {
node.left = new Node(value);
return;
} else if (node.left != null) {
return searchTree(node.left);
}
} else if (value > node.value) {
if (node.right == null) {
node.right = new Node(value);
return;
} else if (node.right != null) {
return searchTree(node.right);
}
} else {
return null;
}
}
var node = this.root;
if (node == null) {
this.root = new Node(value);
return;
} else {
return searchTree(node);
}
}
}
);
--seed-contents--
var displayTree = tree => console.log(JSON.stringify(tree, null, 2));
function Node(value) {
this.value = value;
this.left = null;
this.right = null;
}
function BinarySearchTree() {
this.root = null;
// Only change code below this line
// Only change code above this line
}
--solutions--
var displayTree = tree => console.log(JSON.stringify(tree, null, 2));
function Node(value) {
this.value = value;
this.left = null;
this.right = null;
}
function BinarySearchTree() {
this.root = null;
// Only change code below this line
this.levelOrder = (root = this.root) => {
if(!root) return null;
let queue = [root];
let results = [];
while(queue.length > 0) {
let node = queue.shift();
results.push(node.value);
if(node.left) queue.push(node.left);
if(node.right) queue.push(node.right);
}
return results;
}
this.reverseLevelOrder = (root = this.root) => {
if(!root) return null;
let queue = [root];
let results = [] ;
while ( queue.length > 0) {
let node = queue.shift();
results.push(node.value);
if(node.right) queue.push(node.right);
if(node.left ) queue.push(node.left);
}
return results;
}
// Only change code above this line
}