ee1e8abd87
* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
105 lines
2.5 KiB
Markdown
105 lines
2.5 KiB
Markdown
---
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id: 595608ff8bcd7a50bd490181
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title: Hailstone sequence
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challengeType: 5
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forumTopicId: 302279
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dashedName: hailstone-sequence
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---
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# --description--
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The Hailstone sequence of numbers can be generated from a starting positive integer, `n` by:
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<ul>
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<li>If <code>n</code> is <code>1</code> then the sequence ends</li>
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<li>If <code>n</code> is <code>even</code> then the next <code>n</code> of the sequence <code>= n/2</code></li>
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<li>If <code>n</code> is <code>odd</code> then the next <code>n</code> of the sequence <code>= (3 * n) + 1</code></li>
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</ul>
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The (unproven) [Collatz conjecture](<https://en.wikipedia.org/wiki/Collatz conjecture> "wp: Collatz conjecture") is that the hailstone sequence for any starting number always terminates.
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The hailstone sequence is also known as hailstone numbers (because the values are usually subject to multiple descents and ascents like hailstones in a cloud), or as the Collatz sequence.
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# --instructions--
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<ol>
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<li>Create a routine to generate the hailstone sequence for a number</li>
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<li>Use the routine to show that the hailstone sequence for the number 27 has 112 elements starting with <code>27, 82, 41, 124</code> and ending with <code>8, 4, 2, 1</code></li>
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<li>Show the number less than 100,000 which has the longest hailstone sequence together with that sequence's length. (But don't show the actual sequence!)</li>
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</ol>
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**See also:**
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<ul>
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<li><a href='https://xkcd.com/710' target='_blank'>xkcd</a> (humourous).</li>
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</ul>
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# --hints--
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`hailstoneSequence` should be a function.
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```js
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assert(typeof hailstoneSequence === 'function');
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```
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`hailstoneSequence()` should return `[[27,82,41,124,8,4,2,1], [351, 77031]]`
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```js
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assert.deepEqual(hailstoneSequence(), res);
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```
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# --seed--
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## --after-user-code--
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```js
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const res = [[27, 82, 41, 124, 8, 4, 2, 1], [351, 77031]];
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```
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## --seed-contents--
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```js
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function hailstoneSequence() {
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const res = [];
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return res;
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}
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```
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# --solutions--
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```js
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function hailstoneSequence () {
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const res = [];
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function hailstone(n) {
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const seq = [n];
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while (n > 1) {
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n = n % 2 ? 3 * n + 1 : n / 2;
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seq.push(n);
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}
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return seq;
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}
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const h = hailstone(27);
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const hLen = h.length;
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res.push([...h.slice(0, 4), ...h.slice(hLen - 4, hLen)]);
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let n = 0;
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let max = 0;
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for (let i = 100000; --i;) {
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const seq = hailstone(i);
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const sLen = seq.length;
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if (sLen > max) {
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n = i;
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max = sLen;
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}
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}
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res.push([max, n]);
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return res;
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}
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```
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