* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
1.8 KiB
1.8 KiB
id, title, challengeType, forumTopicId, dashedName
id | title | challengeType | forumTopicId | dashedName |
---|---|---|---|---|
5a23c84252665b21eecc801c | Spiral matrix | 5 | 302321 | spiral-matrix |
--description--
Produce a spiral array. A spiral array is a square arrangement of the first N2 natural numbers, where the numbers increase sequentially as you go around the edges of the array spiraling inwards. For example, given 5, produce this array:
0 1 2 3 4 15 16 17 18 5 14 23 24 19 6 13 22 21 20 7 12 11 10 9 8
--hints--
spiralArray
should be a function.
assert(typeof spiralArray == 'function');
spiralArray(3)
should return an array.
assert(Array.isArray(spiralArray(3)));
spiralArray(3)
should return [[0, 1, 2],[7, 8, 3],[6, 5, 4]]
.
assert.deepEqual(spiralArray(3), [
[0, 1, 2],
[7, 8, 3],
[6, 5, 4]
]);
spiralArray(4)
should return [[0, 1, 2, 3],[11, 12, 13, 4],[10, 15, 14, 5],[9, 8, 7, 6]]
.
assert.deepEqual(spiralArray(4), [
[0, 1, 2, 3],
[11, 12, 13, 4],
[10, 15, 14, 5],
[9, 8, 7, 6]
]);
spiralArray(5)
should return [[0, 1, 2, 3, 4],[15, 16, 17, 18, 5],[14, 23, 24, 19, 6],[13, 22, 21, 20, 7],[12, 11, 10, 9, 8]]
.
assert.deepEqual(spiralArray(5), [
[0, 1, 2, 3, 4],
[15, 16, 17, 18, 5],
[14, 23, 24, 19, 6],
[13, 22, 21, 20, 7],
[12, 11, 10, 9, 8]
]);
--seed--
--seed-contents--
function spiralArray(n) {
}
--solutions--
function spiralArray(n) {
var arr = Array(n),
x = 0,
y = n,
total = n * n--,
dx = 1,
dy = 0,
i = 0,
j = 0;
while (y) arr[--y] = [];
while (i < total) {
arr[y][x] = i++;
x += dx;
y += dy;
if (++j == n) {
if (dy < 0) {
x++;
y++;
n -= 2;
}
j = dx;
dx = -dy;
dy = j;
j = 0;
}
}
return arr;
}