2.6 KiB
2.6 KiB
id, title, challengeType, forumTopicId, dashedName
id | title | challengeType | forumTopicId | dashedName |
---|---|---|---|---|
5a23c84252665b21eecc8028 | Stern-Brocot sequence | 5 | 302324 | stern-brocot-sequence |
--description--
For this task, the Stern-Brocot sequence is to be generated by an algorithm similar to that employed in generating the Fibonacci sequence.
- The first and second members of the sequence are both 1:
- 1, 1
- Start by considering the second member of the sequence
- Sum the considered member of the sequence and its precedent, (1 + 1) = 2, and append it to the end of the sequence:
- 1, 1, 2
- Append the considered member of the sequence to the end of the sequence:
- 1, 1, 2, 1
- Consider the next member of the series, (the third member i.e. 2)
- GOTO 3
- ─── Expanding another loop we get: ───
- Sum the considered member of the sequence and its precedent, (2 + 1) = 3, and append it to the end of the sequence:
- 1, 1, 2, 1, 3
- Append the considered member of the sequence to the end of the sequence:
- 1, 1, 2, 1, 3, 2
- Consider the next member of the series, (the fourth member i.e. 1)
--instructions--
Create a function that returns the position in the Stern-Brocot sequence at which n
is first encountered, where the sequence is generated with the method outlined above. Note that this sequence uses 1 based indexing.
--hints--
sternBrocot
should be a function.
assert(typeof sternBrocot == 'function');
sternBrocot(2)
should return a number.
assert(typeof sternBrocot(2) == 'number');
sternBrocot(2)
should return 3
.
assert.equal(sternBrocot(2), 3);
sternBrocot(3)
should return 5
.
assert.equal(sternBrocot(3), 5);
sternBrocot(5)
should return 11
.
assert.equal(sternBrocot(5), 11);
sternBrocot(7)
should return 19
.
assert.equal(sternBrocot(7), 19);
sternBrocot(10)
should return 39
.
assert.equal(sternBrocot(10), 39);
--seed--
--seed-contents--
function sternBrocot(num) {
}
--solutions--
function sternBrocot(num) {
function f(n) {
return n < 2
? n
: n & 1
? f(Math.floor(n / 2)) + f(Math.floor(n / 2 + 1))
: f(Math.floor(n / 2));
}
function gcd(a, b) {
return a ? (a < b ? gcd(b % a, a) : gcd(a % b, b)) : b;
}
var n;
for (n = 1; f(n) != num; n++);
return n;
}