Oliver Eyton-Williams ee1e8abd87
feat(curriculum): restore seed + solution to Chinese (#40683)
* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
2021-01-12 19:31:00 -07:00

125 lines
2.9 KiB
Markdown

---
id: 594faaab4e2a8626833e9c3d
title: Tokenize a string with escaping
challengeType: 5
forumTopicId: 302338
dashedName: tokenize-a-string-with-escaping
---
# --description--
Write a function or program that can split a string at each non-escaped occurrence of a separator character.
It should accept three input parameters:
<ul>
<li>The <strong>string</strong></li>
<li>The <strong>separator character</strong></li>
<li>The <strong>escape character</strong></li>
</ul>
It should output a list of strings.
Rules for splitting:
<ul>
<li>The fields that were separated by the separators, become the elements of the output list.</li>
<li>Empty fields should be preserved, even at the start and end.</li>
</ul>
Rules for escaping:
<ul>
<li>"Escaped" means preceded by an occurrence of the escape character that is not already escaped itself.</li>
<li>When the escape character precedes a character that has no special meaning, it still counts as an escape (but does not do anything special).</li>
<li>Each occurrences of the escape character that was used to escape something, should not become part of the output.</li>
</ul>
Demonstrate that your function satisfies the following test-case:
Given the string
<pre>one^|uno||three^^^^|four^^^|^cuatro|</pre>
and using `|` as a separator and `^` as escape character, your function should output the following array:
<pre> ['one|uno', '', 'three^^', 'four^|cuatro', '']
</pre>
# --hints--
`tokenize` should be a function.
```js
assert(typeof tokenize === 'function');
```
`tokenize` should return an array.
```js
assert(typeof tokenize('a', 'b', 'c') === 'object');
```
`tokenize('one^|uno||three^^^^|four^^^|^cuatro|', '|', '^')` should return `['one|uno', '', 'three^^', 'four^|cuatro', '']`
```js
assert.deepEqual(tokenize(testStr1, '|', '^'), res1);
```
`tokenize('a@&bcd&ef&&@@hi', '&', '@')` should return `['a&bcd', 'ef', '', '@hi']`
```js
assert.deepEqual(tokenize(testStr2, '&', '@'), res2);
```
# --seed--
## --after-user-code--
```js
const testStr1 = 'one^|uno||three^^^^|four^^^|^cuatro|';
const res1 = ['one|uno', '', 'three^^', 'four^|cuatro', ''];
// TODO add more tests
const testStr2 = 'a@&bcd&ef&&@@hi';
const res2 = ['a&bcd', 'ef', '', '@hi'];
```
## --seed-contents--
```js
function tokenize(str, sep, esc) {
return true;
}
```
# --solutions--
```js
// tokenize :: String -> Character -> Character -> [String]
function tokenize(str, charDelim, charEsc) {
const dctParse = str.split('')
.reduce((a, x) => {
const blnEsc = a.esc;
const blnBreak = !blnEsc && x === charDelim;
const blnEscChar = !blnEsc && x === charEsc;
return {
esc: blnEscChar,
token: blnBreak ? '' : (
a.token + (blnEscChar ? '' : x)
),
list: a.list.concat(blnBreak ? a.token : [])
};
}, {
esc: false,
token: '',
list: []
});
return dctParse.list.concat(
dctParse.token
);
}
```