* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
125 lines
2.9 KiB
Markdown
125 lines
2.9 KiB
Markdown
---
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id: 594faaab4e2a8626833e9c3d
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title: Tokenize a string with escaping
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challengeType: 5
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forumTopicId: 302338
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dashedName: tokenize-a-string-with-escaping
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---
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# --description--
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Write a function or program that can split a string at each non-escaped occurrence of a separator character.
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It should accept three input parameters:
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<ul>
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<li>The <strong>string</strong></li>
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<li>The <strong>separator character</strong></li>
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<li>The <strong>escape character</strong></li>
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</ul>
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It should output a list of strings.
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Rules for splitting:
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<ul>
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<li>The fields that were separated by the separators, become the elements of the output list.</li>
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<li>Empty fields should be preserved, even at the start and end.</li>
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</ul>
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Rules for escaping:
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<ul>
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<li>"Escaped" means preceded by an occurrence of the escape character that is not already escaped itself.</li>
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<li>When the escape character precedes a character that has no special meaning, it still counts as an escape (but does not do anything special).</li>
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<li>Each occurrences of the escape character that was used to escape something, should not become part of the output.</li>
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</ul>
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Demonstrate that your function satisfies the following test-case:
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Given the string
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<pre>one^|uno||three^^^^|four^^^|^cuatro|</pre>
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and using `|` as a separator and `^` as escape character, your function should output the following array:
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<pre> ['one|uno', '', 'three^^', 'four^|cuatro', '']
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</pre>
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# --hints--
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`tokenize` should be a function.
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```js
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assert(typeof tokenize === 'function');
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```
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`tokenize` should return an array.
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```js
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assert(typeof tokenize('a', 'b', 'c') === 'object');
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```
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`tokenize('one^|uno||three^^^^|four^^^|^cuatro|', '|', '^')` should return `['one|uno', '', 'three^^', 'four^|cuatro', '']`
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```js
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assert.deepEqual(tokenize(testStr1, '|', '^'), res1);
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```
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`tokenize('a@&bcd&ef&&@@hi', '&', '@')` should return `['a&bcd', 'ef', '', '@hi']`
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```js
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assert.deepEqual(tokenize(testStr2, '&', '@'), res2);
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```
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# --seed--
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## --after-user-code--
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```js
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const testStr1 = 'one^|uno||three^^^^|four^^^|^cuatro|';
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const res1 = ['one|uno', '', 'three^^', 'four^|cuatro', ''];
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// TODO add more tests
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const testStr2 = 'a@&bcd&ef&&@@hi';
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const res2 = ['a&bcd', 'ef', '', '@hi'];
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```
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## --seed-contents--
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```js
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function tokenize(str, sep, esc) {
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return true;
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}
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```
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# --solutions--
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```js
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// tokenize :: String -> Character -> Character -> [String]
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function tokenize(str, charDelim, charEsc) {
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const dctParse = str.split('')
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.reduce((a, x) => {
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const blnEsc = a.esc;
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const blnBreak = !blnEsc && x === charDelim;
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const blnEscChar = !blnEsc && x === charEsc;
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return {
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esc: blnEscChar,
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token: blnBreak ? '' : (
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a.token + (blnEscChar ? '' : x)
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),
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list: a.list.concat(blnBreak ? a.token : [])
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};
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}, {
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esc: false,
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token: '',
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list: []
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});
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return dctParse.list.concat(
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dctParse.token
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);
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}
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```
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