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freeCodeCamp/curriculum/challenges/english/10-coding-interview-prep/project-euler/problem-188-the-hyperexponentiation-of-a-number.md
Oliver Eyton-Williams ee1e8abd87 feat(curriculum): restore seed + solution to Chinese (#40683)
* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
2021-01-12 19:31:00 -07:00

809 B

id, title, challengeType, forumTopicId, dashedName
id title challengeType forumTopicId dashedName
5900f4291000cf542c50ff3b Problem 188: The hyperexponentiation of a number 5 301824 problem-188-the-hyperexponentiation-of-a-number

--description--

The hyperexponentiation or tetration of a number a by a positive integer b, denoted by a↑↑b or ba, is recursively defined by:

a↑↑1 = a,

a↑↑(k+1) = a(a↑↑k).

Thus we have e.g. 3↑↑2 = 33 = 27, hence 3↑↑3 = 327 = 7625597484987 and 3↑↑4 is roughly 103.6383346400240996*10^12. Find the last 8 digits of 1777↑↑1855.

--hints--

euler188() should return 95962097.

assert.strictEqual(euler188(), 95962097);

--seed--

--seed-contents--

function euler188() {

  return true;
}

euler188();

--solutions--

// solution required