freeCodeCamp/curriculum/challenges/chinese/02-javascript-algorithms-and-data-structures/basic-javascript/comparison-with-the-less-than-operator.chinese.md

id, title, challengeType, videoUrl, localeTitle

id	title	challengeType	videoUrl	localeTitle
56533eb9ac21ba0edf2244d6	Comparison with the Less Than Operator	1		与小于算子的比较

Description

小于运算符（ < ）比较两个数字的值。如果左边的数字小于右边的数字，则返回true 。否则，它返回false 。与等于运算符一样， 少于运算符在比较时转换数据类型。 例子

2 <5 //是的
'3'<7 //是的
5 <5 //假
3 <2 //假
'8'<4 //假

Instructions

将less than运算符添加到指示的行，以便返回语句有意义。

Tests

tests:
  - text: <code>testLessThan(0)</code>应该返回“25岁以下”
    testString: 'assert(testLessThan(0) === "Under 25", "<code>testLessThan(0)</code> should return "Under 25"");'
  - text: <code>testLessThan(24)</code>应该返回“25岁以下”
    testString: 'assert(testLessThan(24) === "Under 25", "<code>testLessThan(24)</code> should return "Under 25"");'
  - text: <code>testLessThan(25)</code>应该返回“55岁以下”
    testString: 'assert(testLessThan(25) === "Under 55", "<code>testLessThan(25)</code> should return "Under 55"");'
  - text: <code>testLessThan(54)</code>应该返回“55岁以下”
    testString: 'assert(testLessThan(54) === "Under 55", "<code>testLessThan(54)</code> should return "Under 55"");'
  - text: <code>testLessThan(55)</code>应返回“55或以上”
    testString: 'assert(testLessThan(55) === "55 or Over", "<code>testLessThan(55)</code> should return "55 or Over"");'
  - text: <code>testLessThan(99)</code>应返回“55或以上”
    testString: 'assert(testLessThan(99) === "55 or Over", "<code>testLessThan(99)</code> should return "55 or Over"");'
  - text: 您应该至少使用<code>&lt;</code>运算符两次
    testString: 'assert(code.match(/val\s*<\s*("|")*\d+("|")*/g).length > 1, "You should use the <code>&lt;</code> operator at least twice");'

Challenge Seed

function testLessThan(val) {
  if (val) {  // Change this line
    return "Under 25";
  }

  if (val) {  // Change this line
    return "Under 55";
  }

  return "55 or Over";
}

// Change this value to test
testLessThan(10);

Solution

// solution required