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- Remove image of phantom - Remove notes for contributors - Links to bottom and to markdown + some more - Alternative code solution ### Notes: - The guide article mentions the challenge can be solved by using `reduce()` but I couldn't find a way to do so. It might be better to remove that reference and the bottom link until someone provides one. - The alternative code solution I provided uses a simpler way (in my opinion) to check if the values are integers but does not differ much from the original one. If necessary, feel free to remove it and go on with just the fixes.
3.4 KiB
3.4 KiB
title
| title |
|---|
| Write Higher Order Arrow Functions |
Remember to use Read-Search-Ask if you get stuck. Try to pair program 
and write your own code 
Problem explanation:
We need to compute and square values from the realNumberArray and store them in the variable squaredIntegers using the map(), filter(), and/or reduce() functions.
Hint: 1
- You will need to
filter()therealNumberArrayfor positive integers (decimals are not integers).
try to solve the problem now
Hint: 2
- You will need to
map()the values from yourfilter()function to the variablesquaredIntegers.
try to solve the problem now
Hint: 3
- Remember the magic of chaining functions.
try to solve the problem now
Spoiler alert!
Solution ahead!
Code solution:
const squareList = (arr) => {
"use strict";
const squaredIntegers = arr.filter( (num) => num > 0 && num % parseInt(num) === 0 ).map( (num) => Math.pow(num, 2) );
return squaredIntegers;
};
// test your code
const squaredIntegers = squareList(realNumberArray);
console.log(squaredIntegers);
Code explanation:
Uses the operator filter() and map() functions to square all positive integers in a given array.
Alternative code solution:
// change code below this line
const squaredIntegers = arr.filter((param) => Number.isInteger(param) && param >= 0).map(x => x * x);
// change code above this line
Code explanation
This does basically the same but uses the isInteger() method to check the numbers.