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freeCodeCamp/guide/english/certifications/coding-interview-prep/rosetta-code/knights-tour/index.md
mrugesh 91df817cfe fix(guide) add stubs, update spellings and prepare for move (#36531)
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* fix: renamed knight's tour to knights-tour

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2019-07-30 00:25:58 +05:30

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---
title: Knight's tour
---
# Knight's tour
---
## Solutions
<details><summary>Solution 1 (Click to Show/Hide)</summary>
```javascript
function knightTour (w, h) {
var b, cnt=0;
var dx = [ -2, -2, -1, 1, 2, 2, 1, -1 ];
var dy = [ -1, 1, 2, 2, 1, -1, -2, -2 ];
function init_board()
{
var i, j, k, x, y;
// * b is board; a is board with 2 rows padded at each side
for(i=0;i<h;i++){
for(j=0;j<w;j++){
b[i][j]=255
}
}
for (i = 0; i < h; i++) {
for (j = 0; j < w; j++) {
for (k = 0; k < 8; k++) {
x = j + dx[k], y = i + dy[k];
if (b[i][j] == 255) b[i][j] = 0;
if(x >= 0 && x < w && y >= 0 && y < h) b[i][j]++;
}
}
}
}
function walk_board(x, y)
{
var i, nx, ny, least;
var steps = 0;
// printf(E"H"E"J"E"%d;%dH"E"32m[]"E"m", y + 1, 1 + 2 * x);
while (1) {
// * occupy cell
b[y][x] = 255;
// * reduce all neighbors' neighbor count
for (i = 0; i < 8; i++)
if(y+dy[i] >= 0 && x+dx[i] >= 0 && y+dy[i] < h && x+dx[i] < w)
b[ y + dy[i] ][ x + dx[i] ]--;
// find neighbor with lowest neighbor count
least = 255;
for (i = 0; i < 8; i++) {
if(y+dy[i] >= 0 && x+dx[i] >= 0 && y+dy[i] < h && x+dx[i] < w)
if (b[ y + dy[i] ][ x + dx[i] ] < least) {
nx = x + dx[i];
ny = y + dy[i];
least = b[ny][nx];
}
}
if (least > 7) {
return steps == w * h - 1;
}
steps++;
x = nx, y = ny;
}
}
function solve (x, y) {
b=new Array(h);
for(var i=0;i<h;i++)
b[i]=new Array(w)
init_board();
if (walk_board(x, y)) {
cnt++;
}
}
for(var i=0;i<h;i++){
for(var j=0;j<w;j++){
solve(j, i);
}
}
return cnt;
}
```
</details>