freeCodeCamp/curriculum/challenges/chinese-traditional/06-quality-assurance/quality-assurance-and-testing-with-chai/test-if-a-string-contains-a-substring.md

id, title, challengeType, forumTopicId, dashedName

id	title	challengeType	forumTopicId	dashedName
587d824d367417b2b2512c53	測試字符串是否包含子字符串	2	301597	test-if-a-string-contains-a-substring

--description--

請注意，本項目在這個 Replit 項目的基礎上進行開發。你也可以從 GitHub 上克隆。

include() 和 notInclude() 同樣可以用於字符串。 include() 用於斷言字符串中包含某個子字符串。

--instructions--

在 tests/1_unit-tests.js 中，Strings 套件裏標有 #14 的測試下，將每個 assert 改成 assert.include 或 assert.notInclude 方法，通過測試（結果應該返回 true）。 不要修改傳給斷言的參數。

--hints--

應通過所有測試。

(getUserInput) =>
  $.get(getUserInput('url') + '/_api/get-tests?type=unit&n=13').then(
    (data) => {
      assert.equal(data.state, 'passed');
    },
    (xhr) => {
      throw new Error(xhr.responseText);
    }
  );

應該爲第一個斷言選擇正確的方法：include 或 notInclude。

(getUserInput) =>
  $.get(getUserInput('url') + '/_api/get-tests?type=unit&n=13').then(
    (data) => {
      assert.equal(
        data.assertions[0].method,
        'include',
        "'Arrow' contains 'row'..."
      );
    },
    (xhr) => {
      throw new Error(xhr.responseText);
    }
  );

應該爲第二個斷言選擇正確的方法：include 或 notInclude。

(getUserInput) =>
  $.get(getUserInput('url') + '/_api/get-tests?type=unit&n=13').then(
    (data) => {
      assert.equal(
        data.assertions[1].method,
        'notInclude',
        "... a 'dart' doesn't contain a 'queue'"
      );
    },
    (xhr) => {
      throw new Error(xhr.responseText);
    }
  );

--solutions--

/**
  Backend challenges don't need solutions, 
  because they would need to be tested against a full working project. 
  Please check our contributing guidelines to learn more.
*/