70 lines
1.4 KiB
Markdown
70 lines
1.4 KiB
Markdown
---
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id: 56533eb9ac21ba0edf2244ae
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title: Finding a Remainder in JavaScript
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challengeType: 1
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videoUrl: 'https://scrimba.com/c/cWP24Ub'
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forumTopicId: 18184
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---
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# --description--
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The <dfn>remainder</dfn> operator `%` gives the remainder of the division of two numbers.
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**Example**
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<blockquote>5 % 2 = 1 because<br>Math.floor(5 / 2) = 2 (Quotient)<br>2 * 2 = 4<br>5 - 4 = 1 (Remainder)</blockquote>
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**Usage**
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In mathematics, a number can be checked to be even or odd by checking the remainder of the division of the number by `2`.
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<blockquote>17 % 2 = 1 (17 is Odd)<br>48 % 2 = 0 (48 is Even)</blockquote>
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**Note**
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The <dfn>remainder</dfn> operator is sometimes incorrectly referred to as the "modulus" operator. It is very similar to modulus, but does not work properly with negative numbers.
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# --instructions--
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Set `remainder` equal to the remainder of `11` divided by `3` using the <dfn>remainder</dfn> (`%`) operator.
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# --hints--
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The variable `remainder` should be initialized
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```js
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assert(/var\s+?remainder/.test(code));
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```
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The value of `remainder` should be `2`
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```js
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assert(remainder === 2);
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```
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You should use the `%` operator
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```js
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assert(/\s+?remainder\s*?=\s*?.*%.*;?/.test(code));
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```
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# --seed--
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## --after-user-code--
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```js
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(function(y){return 'remainder = '+y;})(remainder);
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```
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## --seed-contents--
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```js
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// Only change code below this line
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var remainder;
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```
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# --solutions--
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```js
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var remainder = 11 % 3;
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```
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