Oliver Eyton-Williams 0bd52f8bd1

and change all the challenges to new `md` format.

2020-11-27 10:02:05 -08:00

1.5 KiB

Raw Blame History

id, title, challengeType

id	title	challengeType
5d792533ed00e75d129e1b18	Part 13	0

--description--

replace is a higher order function because it can take a function as argument (higher order functions can also return functions).

Pass the + function from infixToFunction to the replace method as the second argument.

This is how you would pass the - function:

str.replace(regex, infixToFunction["-"])

--hints--

See description above for instructions.

assert(infixEval('ab', /(a)b/) === 'aba');

--seed--

--before-user-code--

<!DOCTYPE html>
<html lang="en">
<head>
  <meta charset="UTF-8">
  <title>Spreadsheet</title>
  <style>
    #container {
      display: grid;
      grid-template-columns: 50px repeat(10, 200px);
      grid-template-rows: repeat(11, 30px);
    }
    .label {
      background-color: lightgray;
      text-align: center;
      vertical-align: middle;
      line-height: 30px;
    }
  </style>
</head>
<body>
<div id="container">
  <div></div>
</div>

--after-user-code--

</body>
</html>

--seed-contents--

<script>

const infixToFunction = {
  "+": (x, y) => x + y,
  "-": (x, y) => x - y,
  "*": (x, y) => x * y,
  "/": (x, y) => x / y
};

const infixEval = (str, regex) => str.replace(regex, "");


</script>

--solutions--

<script>
const infixToFunction = {
  "+": (x, y) => x + y,
  "-": (x, y) => x - y,
  "*": (x, y) => x * y,
  "/": (x, y) => x / y
};

const infixEval = (str, regex) => str.replace(regex, infixToFunction["+"]);
</script>

1.5 KiB Raw Blame History