* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
		
			
				
	
	
		
			114 lines
		
	
	
		
			2.9 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
			
		
		
	
	
			114 lines
		
	
	
		
			2.9 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
| ---
 | |
| id: 5900f3a31000cf542c50feb6
 | |
| title: 'Problem 55: Lychrel numbers'
 | |
| challengeType: 5
 | |
| forumTopicId: 302166
 | |
| dashedName: problem-55-lychrel-numbers
 | |
| ---
 | |
| 
 | |
| # --description--
 | |
| 
 | |
| If we take 47, reverse and add, 47 + 74 = 121, which is palindromic.
 | |
| 
 | |
| Not all numbers produce palindromes so quickly. For example,
 | |
| 
 | |
| <div style="margin-left: 4em;">
 | |
|   349 + 943 = 1292,<br>
 | |
|   1292 + 2921 = 4213<br>
 | |
|   4213 + 3124 = 7337<br>
 | |
| </div>
 | |
| 
 | |
| That is, 349 took three iterations to arrive at a palindrome.
 | |
| 
 | |
| Although no one has proved it yet, it is thought that some numbers, like 196, never produce a palindrome. A number that never forms a palindrome through the reverse and add process is called a Lychrel number. Due to the theoretical nature of these numbers, and for the purpose of this problem, we shall assume that a number is Lychrel until proven otherwise. In addition you are given that for every number below ten-thousand, it will either (i) become a palindrome in less than fifty iterations, or, (ii) no one, with all the computing power that exists, has managed so far to map it to a palindrome. In fact, 10677 is the first number to be shown to require over fifty iterations before producing a palindrome: 4668731596684224866951378664 (53 iterations, 28-digits).
 | |
| 
 | |
| Surprisingly, there are palindromic numbers that are themselves Lychrel numbers; the first example is 4994.
 | |
| 
 | |
| How many Lychrel numbers are there below `num`?
 | |
| 
 | |
| **Note:** Wording was modified slightly on 24 April 2007 to emphasize the theoretical nature of Lychrel numbers.
 | |
| 
 | |
| # --hints--
 | |
| 
 | |
| `countLychrelNumbers(1000)` should return a number.
 | |
| 
 | |
| ```js
 | |
| assert(typeof countLychrelNumbers(1000) === 'number');
 | |
| ```
 | |
| 
 | |
| `countLychrelNumbers(1000)` should return 13.
 | |
| 
 | |
| ```js
 | |
| assert.strictEqual(countLychrelNumbers(1000), 13);
 | |
| ```
 | |
| 
 | |
| `countLychrelNumbers(3243)` should return 39.
 | |
| 
 | |
| ```js
 | |
| assert.strictEqual(countLychrelNumbers(3243), 39);
 | |
| ```
 | |
| 
 | |
| `countLychrelNumbers(5000)` should return 76.
 | |
| 
 | |
| ```js
 | |
| assert.strictEqual(countLychrelNumbers(5000), 76);
 | |
| ```
 | |
| 
 | |
| `countLychrelNumbers(7654)` should return 140.
 | |
| 
 | |
| ```js
 | |
| assert.strictEqual(countLychrelNumbers(7654), 140);
 | |
| ```
 | |
| 
 | |
| `countLychrelNumbers(10000)` should return 249.
 | |
| 
 | |
| ```js
 | |
| assert.strictEqual(countLychrelNumbers(10000), 249);
 | |
| ```
 | |
| 
 | |
| # --seed--
 | |
| 
 | |
| ## --seed-contents--
 | |
| 
 | |
| ```js
 | |
| function countLychrelNumbers(num) {
 | |
| 
 | |
|   return true;
 | |
| }
 | |
| 
 | |
| countLychrelNumbers(10000);
 | |
| ```
 | |
| 
 | |
| # --solutions--
 | |
| 
 | |
| ```js
 | |
| const countLychrelNumbers = (size) => {
 | |
|   const numReverse = (num) => {
 | |
|     return Number(num.toString().split('').reverse().join(''));
 | |
|   };
 | |
|   const isPalin = (num) => {
 | |
|     if (numReverse(num) === num) {
 | |
|       return true;
 | |
|     }
 | |
|     return false;
 | |
|   };
 | |
|   let total = 0;
 | |
|   for (let i = 1; i < size; i++) {
 | |
|     let loopCount = 1;
 | |
|     let sum = i;
 | |
|     while (loopCount < 50) {
 | |
|       sum = sum + numReverse(sum);
 | |
|       if (isPalin(sum)) {
 | |
|         break;
 | |
|       } else {
 | |
|         loopCount++;
 | |
|       }
 | |
|     }
 | |
|     if (loopCount === 50) {
 | |
|       total++;
 | |
|     }
 | |
|   }
 | |
|   return total;
 | |
| }
 | |
| ```
 |