freeCodeCamp/curriculum/challenges/02-javascript-algorithms-and-data-structures/basic-javascript/Compound Assignment With Augmented Multiplication.md

id, title, challengeType

id	title	challengeType
56533eb9ac21ba0edf2244b1	Compound Assignment With Augmented Multiplication	1

Description

The *= operator multiplies a variable by a number. myVar = myVar * 5; will multiply myVar by 5. This can be rewritten as: myVar *= 5;

Instructions

Convert the assignments for a, b, and c to use the *= operator.

Tests

- text: <code>a</code> should equal <code>25</code>
  testString: 'assert(a === 25, "<code>a</code> should equal <code>25</code>");'
- text: <code>b</code> should equal <code>36</code>
  testString: 'assert(b === 36, "<code>b</code> should equal <code>36</code>");'
- text: <code>c</code> should equal <code>46</code>
  testString: 'assert(c === 46, "<code>c</code> should equal <code>46</code>");'
- text: You should use the <code>*=</code> operator for each variable
  testString: 'assert(code.match(/\*=/g).length === 3, "You should use the <code>*=</code> operator for each variable");'
- text: Do not modify the code above the line
  testString: 'assert(/var a = 5;/.test(code) && /var b = 12;/.test(code) && /var c = 4\.6;/.test(code), "Do not modify the code above the line");'

Challenge Seed

var a = 5;
var b = 12;
var c = 4.6;

// Only modify code below this line

a = a * 5;
b = 3 * b;
c = c * 10;

After Test

console.info('after the test');

Solution

var a = 5;
var b = 12;
var c = 4.6;

a *= 5;
b *= 3;
c *= 10;