* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
		
			
				
	
	
		
			80 lines
		
	
	
		
			1.7 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
			
		
		
	
	
			80 lines
		
	
	
		
			1.7 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
| ---
 | |
| id: 596fda99c69f779975a1b67d
 | |
| title: Count occurrences of a substring
 | |
| challengeType: 5
 | |
| forumTopicId: 302237
 | |
| dashedName: count-occurrences-of-a-substring
 | |
| ---
 | |
| 
 | |
| # --description--
 | |
| 
 | |
| Create a function, or show a built-in function, to count the number of non-overlapping occurrences of a substring inside a string.
 | |
| 
 | |
| The function should take two arguments:
 | |
| 
 | |
| <ul>
 | |
|   <li>the first argument being the string to search, and</li>
 | |
|   <li>the second a substring to be searched for.</li>
 | |
| </ul>
 | |
| 
 | |
| It should return an integer count.
 | |
| 
 | |
| The matching should yield the highest number of non-overlapping matches.
 | |
| 
 | |
| In general, this essentially means matching from left-to-right or right-to-left.
 | |
| 
 | |
| # --hints--
 | |
| 
 | |
| `countSubstring` should be a function.
 | |
| 
 | |
| ```js
 | |
| assert(typeof countSubstring === 'function');
 | |
| ```
 | |
| 
 | |
| `countSubstring("the three truths", "th")` should return `3`.
 | |
| 
 | |
| ```js
 | |
| assert.equal(countSubstring(testCases[0], searchString[0]), results[0]);
 | |
| ```
 | |
| 
 | |
| `countSubstring("ababababab", "abab")` should return `2`.
 | |
| 
 | |
| ```js
 | |
| assert.equal(countSubstring(testCases[1], searchString[1]), results[1]);
 | |
| ```
 | |
| 
 | |
| `countSubstring("abaabba*bbaba*bbab", "a*b")` should return `2`.
 | |
| 
 | |
| ```js
 | |
| assert.equal(countSubstring(testCases[2], searchString[2]), results[2]);
 | |
| ```
 | |
| 
 | |
| # --seed--
 | |
| 
 | |
| ## --after-user-code--
 | |
| 
 | |
| ```js
 | |
| const testCases = ['the three truths', 'ababababab', 'abaabba*bbaba*bbab'];
 | |
| const searchString = ['th', 'abab', 'a*b'];
 | |
| const results = [3, 2, 2];
 | |
| ```
 | |
| 
 | |
| ## --seed-contents--
 | |
| 
 | |
| ```js
 | |
| function countSubstring(str, subStr) {
 | |
| 
 | |
|   return true;
 | |
| }
 | |
| ```
 | |
| 
 | |
| # --solutions--
 | |
| 
 | |
| ```js
 | |
| function countSubstring(str, subStr) {
 | |
|   const escapedSubStr = subStr.replace(/[.+*?^$[\]{}()|/]/g, '\\$&');
 | |
|   const matches = str.match(new RegExp(escapedSubStr, 'g'));
 | |
|   return matches ? matches.length : 0;
 | |
| }
 | |
| ```
 |