freeCodeCamp/curriculum/challenges/chinese/02-javascript-algorithms-and-data-structures/regular-expressions/match-characters-that-occur-zero-or-more-times.md

id, challengeType, forumTopicId, title

id	challengeType	forumTopicId	title
587d7db6367417b2b2512b9a	1	301351	匹配出现零次或多次的字符

Description

上一次的挑战中使用了加号+来查找出现一次或多次的字符。还有一个选项可以匹配出现零次或多次的字符。 执行该操作的字符叫做asterisk或star，即*。

let soccerWord = "gooooooooal!";
let gPhrase = "gut feeling";
let oPhrase = "over the moon";
let goRegex = /go*/;
soccerWord.match(goRegex); // Returns ["goooooooo"]
gPhrase.match(goRegex); // Returns ["g"]
oPhrase.match(goRegex); // Returns null

Instructions

在这个挑战里，chewieQuote 已经被初始化为 "Aaaaaaaaaaaaaaaarrrgh!"。创建一个变量为chewieRegex的正则表达式，使用*符号在chewieQuote中匹配"A"及其之后出现的零个或多个"a"。你的正则表达式不需要使用修饰符，也不需要匹配引号。

Tests

tests:
  - text: "你的正则表达式<code>chewieRegex</code>应该使用<code>*</code>符号匹配<code>'A'</code>之后出现的零个或多个<code>'a'</code>字符。"
    testString: assert(/\*/.test(chewieRegex.source));
  - text: 正则表达式应当匹配 <code>chewieQuote</code> 里的 <code>"A"</code>。
    testString: assert(result[0][0] === 'A');
  - text: "你的正则表达式应该匹配<code>'Aaaaaaaaaaaaaaaa'</code>。"
    testString: assert(result[0] === 'Aaaaaaaaaaaaaaaa');
  - text: 你的正则表达式<code>chewieRegex</code>应该匹配 16 个字符。
    testString: assert(result[0].length === 16);
  - text: "你的正则表达式在<code>'He made a fair move. Screaming about it can&#39t help you.'</code>中不应该匹配任何字符。"
    testString: assert(!"He made a fair move. Screaming about it can't help you.".match(chewieRegex));
  - text: "你的正则表达式在<code>'Let him have it. It&#39s not wise to upset a Wookiee.'</code>中不应该匹配任何字符。"
    testString: assert(!"Let him have it. It's not wise to upset a Wookiee.".match(chewieRegex));

Challenge Seed

let chewieRegex = /change/; // Only change this line
let result = chewieQuote.match(chewieRegex);

Before Test

const chewieQuote = "Aaaaaaaaaaaaaaaarrrgh!";

Solution

  let chewieRegex = /Aa*/;
  let result = chewieQuote.match(chewieRegex);