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freeCodeCamp/curriculum/challenges/chinese/10-coding-interview-prep/project-euler/problem-30-digit-n-powers.md
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---
id: 5900f38a1000cf542c50fe9d
challengeType: 5
videoUrl: ''
title: 问题30数字n次方
---
## Description
<section id="description">
令人惊讶的是,只有三个数字可以写为它们的数字的四次幂之和:
1634 = 1 <sup> 4 </sup> + 6 <sup> 4 </sup> + 3 <sup> 4 </sup> + 4 <sup> 4 </sup>
8208 = 8 <sup> 4 </sup> + 2 <sup> 4 </sup> + 0 <sup> 4 </sup> + 8 <sup> 4 </sup>
9474 = 9 <sup> 4 </sup> + 4 <sup> 4 </sup> + 7 <sup> 4 </sup> + 4 <sup> 4 </sup>
由于1 = 1 <sup> 4 </sup>不是总和,因此不包括在内。
这些数字的总和为1634 + 8208 + 9474 = 19316。
找出所有可以写为数字n次幂的数字之和。
</section>
## Instructions
<section id="instructions">
</section>
## Tests
<section id='tests'>
```yml
tests:
- text: <code>digitnPowers(2)</code>应该返回0。
testString: assert(digitnPowers(2) == 0);
- text: <code>digitnPowers(3)</code>应该返回1301。
testString: assert(digitnPowers(3) == 1301);
- text: <code>digitnPowers(4)</code>应该返回19316。
testString: assert(digitnPowers(4) == 19316);
- text: <code>digitnPowers(5)</code>应该返回443839。
testString: assert(digitnPowers(5) == 443839);
```
</section>
## Challenge Seed
<section id='challengeSeed'>
<div id='js-seed'>
```js
function digitnPowers(n) {
// Good luck!
return n;
}
digitnPowers(5);
```
</div>
</section>
## Solution
<section id='solution'>
```js
// solution required
```
/section>