* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
1.3 KiB
1.3 KiB
id, title, challengeType, forumTopicId, dashedName
id | title | challengeType | forumTopicId | dashedName |
---|---|---|---|---|
5900f3711000cf542c50fe84 | Problem 5: Smallest multiple | 5 | 302160 | problem-5-smallest-multiple |
--description--
2520 is the smallest number that can be divided by each of the numbers from 1 to 10 without any remainder.
What is the smallest positive number that is evenly divisible by all of the numbers from 1 to n
?
--hints--
smallestMult(5)
should return a number.
assert(typeof smallestMult(5) === 'number');
smallestMult(5)
should return 60.
assert.strictEqual(smallestMult(5), 60);
smallestMult(7)
should return 420.
assert.strictEqual(smallestMult(7), 420);
smallestMult(10)
should return 2520.
assert.strictEqual(smallestMult(10), 2520);
smallestMult(13)
should return 360360.
assert.strictEqual(smallestMult(13), 360360);
smallestMult(20)
should return 232792560.
assert.strictEqual(smallestMult(20), 232792560);
--seed--
--seed-contents--
function smallestMult(n) {
return true;
}
smallestMult(20);
--solutions--
function smallestMult(n){
function gcd(a, b) {
return b === 0 ? a : gcd(b, a%b); // Euclidean algorithm
}
function lcm(a, b) {
return a * b / gcd(a, b);
}
var result = 1;
for(var i = 2; i <= n; i++) {
result = lcm(result, i);
}
return result;
}