freeCodeCamp/problem-20-factorial-digit-sum.english.md at 8f39bc12887a251fc7146e6d288de44ba279612f

Files

Bouncey 8f39bc1288 chore(curriculum): Remove files in wrong format

2018-10-05 15:58:12 +01:00

1.7 KiB

Raw Blame History

id, challengeType, title

id	challengeType	title
5900f3801000cf542c50fe93	5	Problem 20: Factorial digit sum

Description

n! means n × (n − 1) × ... × 3 × 2 × 1 For example, 10! = 10 × 9 × ... × 3 × 2 × 1 = 3628800,
and the sum of the digits in the number 10! is 3 + 6 + 2 + 8 + 8 + 0 + 0 = 27. Find the sum of the digits n!

Instructions

Tests

tests:
  - text: <code>sumFactorialDigits(10)</code> should return 27.
    testString: 'assert.strictEqual(sumFactorialDigits(10), 27, ''<code>sumFactorialDigits(10)</code> should return 27.'');'
  - text: <code>sumFactorialDigits(25)</code> should return 72.
    testString: 'assert.strictEqual(sumFactorialDigits(25), 72, ''<code>sumFactorialDigits(25)</code> should return 72.'');'
  - text: <code>sumFactorialDigits(50)</code> should return 216.
    testString: 'assert.strictEqual(sumFactorialDigits(50), 216, ''<code>sumFactorialDigits(50)</code> should return 216.'');'
  - text: <code>sumFactorialDigits(75)</code> should return 432.
    testString: 'assert.strictEqual(sumFactorialDigits(75), 432, ''<code>sumFactorialDigits(75)</code> should return 432.'');'
  - text: <code>sumFactorialDigits(100)</code> should return 648.
    testString: 'assert.strictEqual(sumFactorialDigits(100), 648, ''<code>sumFactorialDigits(100)</code> should return 648.'');'

Challenge Seed

function sumFactorialDigits(n) {
  // Good luck!
  return n;
}

sumFactorialDigits(100);

Solution

// solution required

1.7 KiB Raw Blame History Unescape Escape