freeCodeCamp/problem-474-last-digits-of-divisors.english.md at 908adc2c372f2c1af0c8d1c80b264c23f96fd7d7

mrugesh 22afc2a0ca feat(learn): python certification projects (#38216 )

Co-authored-by: Oliver Eyton-Williams <ojeytonwilliams@gmail.com>
Co-authored-by: Kristofer Koishigawa <scissorsneedfoodtoo@gmail.com>
Co-authored-by: Beau Carnes <beaucarnes@gmail.com>

2020-05-27 13:19:08 +05:30

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id, challengeType, isHidden, title, forumTopicId

id	challengeType	isHidden	title	forumTopicId
5900f5471000cf542c510059	5	false	Problem 474: Last digits of divisors	302151

Description

For a positive integer n and digits d, we define F(n, d) as the number of the divisors of n whose last digits equal d. For example, F(84, 4) = 3. Among the divisors of 84 (1, 2, 3, 4, 6, 7, 12, 14, 21, 28, 42, 84), three of them (4, 14, 84) have the last digit 4.

We can also verify that F(12!, 12) = 11 and F(50!, 123) = 17888.

Find F(106!, 65432) modulo (1016 + 61).

Instructions

Tests

tests:
  - text: <code>euler474()</code> should return 9690646731515010.
    testString: assert.strictEqual(euler474(), 9690646731515010);

Challenge Seed

function euler474() {
  // Good luck!
  return true;
}

euler474();

Solution

// solution required

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