freeCodeCamp/curriculum/challenges/english/10-coding-interview-prep/project-euler/problem-90-cube-digit-pairs.english.md

id, challengeType, isHidden, title, forumTopicId

id	challengeType	isHidden	title	forumTopicId
5900f3c61000cf542c50fed9	5	false	Problem 90: Cube digit pairs	302207

Description

Each of the six faces on a cube has a different digit (0 to 9) written on it; the same is done to a second cube. By placing the two cubes side-by-side in different positions we can form a variety of 2-digit numbers.

For example, the square number 64 could be formed:

In fact, by carefully choosing the digits on both cubes it is possible to display all of the square numbers below one-hundred: 01, 04, 09, 16, 25, 36, 49, 64, and 81.

For example, one way this can be achieved is by placing {0, 5, 6, 7, 8, 9} on one cube and {1, 2, 3, 4, 8, 9} on the other cube.

However, for this problem we shall allow the 6 or 9 to be turned upside-down so that an arrangement like {0, 5, 6, 7, 8, 9} and {1, 2, 3, 4, 6, 7} allows for all nine square numbers to be displayed; otherwise it would be impossible to obtain 09.

In determining a distinct arrangement we are interested in the digits on each cube, not the order.

{1, 2, 3, 4, 5, 6} is equivalent to {3, 6, 4, 1, 2, 5}
{1, 2, 3, 4, 5, 6} is distinct from {1, 2, 3, 4, 5, 9}

But because we are allowing 6 and 9 to be reversed, the two distinct sets in the last example both represent the extended set {1, 2, 3, 4, 5, 6, 9} for the purpose of forming 2-digit numbers.

How many distinct arrangements of the two cubes allow for all of the square numbers to be displayed?

Instructions

Tests

tests:
  - text: <code>cubeDigitPairs()</code> should return a number.
    testString: assert(typeof cubeDigitPairs() === 'number');
  - text: <code>cubeDigitPairs()</code> should return 1217.
    testString: assert.strictEqual(cubeDigitPairs(), 1217);

Challenge Seed

function cubeDigitPairs() {
  // Good luck!
  return true;
}

cubeDigitPairs();

Solution

// solution required