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2019-07-30 00:25:58 +05:30

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title
title
Problem 1: Multiples of 3 and 5

Problem 1: Multiples of 3 and 5


Problem Explanation

  • We can find if a number is divisble by another number with the help of % modulo operator.
  • num1 % num2 returns 0 if there's no remainder while doing num1/num2.
  • Starting from i = 3 because that's the first number that's divisble by 3 or 5, we loop through till the number provided.
  • If the number is divisible either by 3 or 5, we add that to the variable sum and finally return it.

Solutions

Solution 1 (Click to Show/Hide)
function multiplesOf3and5(number) {
  let sum = 0,
    i = 3;
  while (i < number) {
    if (i % 3 == 0 || i % 5 == 0) sum += i;
    i++;
  }
  return sum;
}