56 lines
		
	
	
		
			1.1 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
			
		
		
	
	
			56 lines
		
	
	
		
			1.1 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
| ---
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| id: 5900f3b21000cf542c50fec5
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| challengeType: 5
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| title: 'Problem 70: Totient permutation'
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| videoUrl: ''
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| localeTitle: 问题70欧拉置换
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| ---
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| 
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| ## Description
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| <section id="description"> Euler的Totient函数φ(n)[有时称为phi函数]用于确定小于或等于n的正数的数量,它们是n的相对素数。例如,如1,2,4,5,7和8都小于9且相对素数为9,φ(9)= 6.数字1被认为是每个正数的相对素数,所以φ(1)= 1。有趣的是,φ(87109)= 79180,可以看出87109是79180的置换。找到n的值,1 <n <107,其中φ(n)是n的置换和比率n / φ(n)产生最小值。 </section>
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| 
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| ## Instructions
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| <section id="instructions">
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| </section>
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| 
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| ## Tests
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| <section id='tests'>
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| 
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| ```yml
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| tests:
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|   - text: <code>euler70()</code>应该返回8319823。
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|     testString: 'assert.strictEqual(euler70(), 8319823, "<code>euler70()</code> should return 8319823.");'
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| 
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| ```
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| 
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| </section>
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| 
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| ## Challenge Seed
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| <section id='challengeSeed'>
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| 
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| <div id='js-seed'>
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| 
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| ```js
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| function euler70() {
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|   // Good luck!
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|   return true;
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| }
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| 
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| euler70();
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| 
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| ```
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| 
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| </div>
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| 
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| 
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| 
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| </section>
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| 
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| ## Solution
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| <section id='solution'>
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| 
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| ```js
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| // solution required
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| ```
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| </section>
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