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freeCodeCamp/curriculum/challenges/english/02-javascript-algorithms-and-data-structures/basic-javascript/finding-a-remainder-in-javascript.md
Nicholas Carrigan (he/him) 7117919d36 chore(learn): audit javascript algorithms and data structures (#41092)
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* chore: change voice

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Co-authored-by: Randell Dawson <5313213+RandellDawson@users.noreply.github.com>
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Co-authored-by: Oliver Eyton-Williams <ojeytonwilliams@gmail.com>
2021-03-02 17:12:12 -07:00

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---
id: 56533eb9ac21ba0edf2244ae
title: Finding a Remainder in JavaScript
challengeType: 1
videoUrl: 'https://scrimba.com/c/cWP24Ub'
forumTopicId: 18184
dashedName: finding-a-remainder-in-javascript
---
# --description--
The <dfn>remainder</dfn> operator `%` gives the remainder of the division of two numbers.
**Example**
<blockquote>5 % 2 = 1 because<br>Math.floor(5 / 2) = 2 (Quotient)<br>2 * 2 = 4<br>5 - 4 = 1 (Remainder)</blockquote>
**Usage**
In mathematics, a number can be checked to be even or odd by checking the remainder of the division of the number by `2`.
<blockquote>17 % 2 = 1 (17 is Odd)<br>48 % 2 = 0 (48 is Even)</blockquote>
**Note:** The <dfn>remainder</dfn> operator is sometimes incorrectly referred to as the modulus operator. It is very similar to modulus, but does not work properly with negative numbers.
# --instructions--
Set `remainder` equal to the remainder of `11` divided by `3` using the <dfn>remainder</dfn> (`%`) operator.
# --hints--
The variable `remainder` should be initialized
```js
assert(/var\s+?remainder/.test(code));
```
The value of `remainder` should be `2`
```js
assert(remainder === 2);
```
You should use the `%` operator
```js
assert(/\s+?remainder\s*?=\s*?.*%.*;?/.test(code));
```
# --seed--
## --after-user-code--
```js
(function(y){return 'remainder = '+y;})(remainder);
```
## --seed-contents--
```js
// Only change code below this line
var remainder;
```
# --solutions--
```js
var remainder = 11 % 3;
```