freeCodeCamp/curriculum/challenges/chinese/08-coding-interview-prep/project-euler/problem-6-sum-square-difference.chinese.md

id, challengeType, title, videoUrl, localeTitle

id	challengeType	title	videoUrl	localeTitle
5900f3721000cf542c50fe85	5	Problem 6: Sum square difference		问题6：求和方差

Description

前十个自然数的平方和是，

1 ² + 2 ² + ... + 10 ² = 385

前十个自然数之和的平方是，

（1 + 2 + ... + 10） ² = 55 ² = 3025

因此，前十个自然数的平方和与和的平方之间的差值为3025 - 385 = 2640.求出前n自然数的平方和与总和的平方之间的差值。

Instructions

Tests

tests:
  - text: <code>sumSquareDifference(10)</code>应该返回2640。
    testString: 'assert.strictEqual(sumSquareDifference(10), 2640, "<code>sumSquareDifference(10)</code> should return 2640.");'
  - text: <code>sumSquareDifference(20)</code>应该返回41230。
    testString: 'assert.strictEqual(sumSquareDifference(20), 41230, "<code>sumSquareDifference(20)</code> should return 41230.");'
  - text: <code>sumSquareDifference(100)</code>应该返回25164150。
    testString: 'assert.strictEqual(sumSquareDifference(100), 25164150, "<code>sumSquareDifference(100)</code> should return 25164150.");'

Challenge Seed

function sumSquareDifference(n) {
  // Good luck!
  return true;
}

sumSquareDifference(100);

Solution

// solution required