56 lines
		
	
	
		
			1.0 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
			
		
		
	
	
			56 lines
		
	
	
		
			1.0 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
| ---
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| id: 5900f5361000cf542c510048
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| challengeType: 5
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| title: 'Problem 457: A polynomial modulo the square of a prime'
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| videoUrl: ''
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| localeTitle: 问题457:多项式以素数的平方为模
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| ---
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| 
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| ## Description
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| <section id="description">设f(n)= n2  -  3n  -  1.设p为素数。令R(p)是最小的正整数n,使得如果存在这样的整数n则f(n)mod p2 = 0,否则R(p)= 0。 <p>对于不超过L的所有素数,令SR(L)为ΣR(p)。 </p><p>找到SR(107)。 </p></section>
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| 
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| ## Instructions
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| <section id="instructions">
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| </section>
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| 
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| ## Tests
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| <section id='tests'>
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| 
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| ```yml
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| tests:
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|   - text: <code>euler457()</code>应该返回2647787126797397000。
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|     testString: 'assert.strictEqual(euler457(), 2647787126797397000, "<code>euler457()</code> should return 2647787126797397000.");'
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| 
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| ```
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| 
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| </section>
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| 
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| ## Challenge Seed
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| <section id='challengeSeed'>
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| 
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| <div id='js-seed'>
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| 
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| ```js
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| function euler457() {
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|   // Good luck!
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|   return true;
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| }
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| 
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| euler457();
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| 
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| ```
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| 
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| </div>
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| 
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| 
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| 
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| </section>
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| 
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| ## Solution
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| <section id='solution'>
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| 
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| ```js
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| // solution required
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| ```
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| </section>
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