5.3 KiB
		
	
	
	
	
	
	
	
			
		
		
	
	
			5.3 KiB
		
	
	
	
	
	
	
	
id, title, challengeType, forumTopicId
| id | title | challengeType | forumTopicId | 
|---|---|---|---|
| 587d8258367417b2b2512c7f | Use Breadth First Search in a Binary Search Tree | 1 | 301718 | 
Description
Instructions
levelOrder. This method should return an array containing the values of all the tree nodes, explored in a breadth-first manner. Be sure to return the values in the array, not the nodes themselves. A level should be traversed from left to right. Next, let's write a similar method called reverseLevelOrder which performs the same search but in the reverse direction (right to left) at each level.
Tests
tests:
  - text: The <code>BinarySearchTree</code> data structure exists.
    testString: assert((function() { var test = false; if (typeof BinarySearchTree !== 'undefined') { test = new BinarySearchTree() }; return (typeof test == 'object')})());
  - text: The binary search tree has a method called <code>levelOrder</code>.
    testString: assert((function() { var test = false; if (typeof BinarySearchTree !== 'undefined') { test = new BinarySearchTree() } else { return false; }; return (typeof test.levelOrder == 'function')})());
  - text: The binary search tree has a method called <code>reverseLevelOrder</code>.
    testString: assert((function() { var test = false; if (typeof BinarySearchTree !== 'undefined') { test = new BinarySearchTree() } else { return false; }; return (typeof test.reverseLevelOrder == 'function')})());
  - text: The <code>levelOrder</code> method returns an array of the tree node values explored in level order.
    testString: assert((function() { var test = false; if (typeof BinarySearchTree !== 'undefined') { test = new BinarySearchTree() } else { return false; }; if (typeof test.levelOrder !== 'function') { return false; }; test.add(7); test.add(1); test.add(9); test.add(0); test.add(3); test.add(8); test.add(10); test.add(2); test.add(5); test.add(4); test.add(6); return (test.levelOrder().join('') == '719038102546'); })());
  - text: The <code>reverseLevelOrder</code> method returns an array of the tree node values explored in reverse level order.
    testString: assert((function() { var test = false; if (typeof BinarySearchTree !== 'undefined') { test = new BinarySearchTree() } else { return false; }; if (typeof test.reverseLevelOrder !== 'function') { return false; }; test.add(7); test.add(1); test.add(9); test.add(0); test.add(3); test.add(8); test.add(10); test.add(2); test.add(5); test.add(4); test.add(6); return (test.reverseLevelOrder().join('') == '791108305264'); })());
  - text: The <code>levelOrder</code> method returns <code>null</code> for an empty tree.
    testString: assert((function() { var test = false; if (typeof BinarySearchTree !== 'undefined') { test = new BinarySearchTree() } else { return false; }; if (typeof test.levelOrder !== 'function') { return false; }; return (test.levelOrder() == null); })());
  - text: The <code>reverseLevelOrder</code> method returns <code>null</code> for an empty tree.
    testString: assert((function() { var test = false; if (typeof BinarySearchTree !== 'undefined') { test = new BinarySearchTree() } else { return false; }; if (typeof test.reverseLevelOrder !== 'function') { return false; }; return (test.reverseLevelOrder() == null); })());
Challenge Seed
var displayTree = tree => console.log(JSON.stringify(tree, null, 2));
function Node(value) {
  this.value = value;
  this.left = null;
  this.right = null;
}
function BinarySearchTree() {
  this.root = null;
  // change code below this line
  // change code above this line
}
After Test
BinarySearchTree.prototype = {
  add: function(value) {
    var node = this.root;
    if (node == null) {
      this.root = new Node(value);
      return;
    } else {
      function searchTree(node) {
        if (value < node.value) {
          if (node.left == null) {
            node.left = new Node(value);
            return;
          } else if (node.left != null) {
            return searchTree(node.left);
          }
        } else if (value > node.value) {
          if (node.right == null) {
            node.right = new Node(value);
            return;
          } else if (node.right != null) {
            return searchTree(node.right);
          }
        } else {
          return null;
        }
      }
      return searchTree(node);
    }
  }
};
Solution
// solution required