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freeCodeCamp/curriculum/challenges/english/08-coding-interview-prep/data-structures/perform-a-difference-on-two-sets-of-data.english.md
2020-04-23 02:14:50 +05:30

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---
id: 587d8254367417b2b2512c6e
title: Perform a Difference on Two Sets of Data
challengeType: 1
forumTopicId: 301706
---
## Description
<section id='description'>
In this exercise we are going to perform a difference on 2 sets of data. We will create a method on our <code>Set</code> data structure called <code>difference</code>. A difference of sets should compare two sets and return the items present in the first set that are absent in the second. This method should take another <code>Set</code> as an argument and return the <code>difference</code> of the two sets.
For example, if <code>setA = ['a','b','c']</code> and <code>setB = ['a','b','d','e']</code>, then the difference of setA and setB is: <code>setA.difference(setB) = ['c']</code>.
</section>
## Instructions
<section id='instructions'>
</section>
## Tests
<section id='tests'>
```yml
tests:
- text: Your <code>Set</code> class should have a <code>difference</code> method.
testString: assert((function(){var test = new Set(); return (typeof test.difference === 'function')})());
- text: Your <code>difference</code> method should return the proper collection.
testString: assert((function(){var setA = new Set(); var setB = new Set(); setA.add('a'); setA.add('b'); setA.add('c'); setB.add('c'); setB.add('d'); var differenceSetAB = setA.difference(setB); return (differenceSetAB.size() === 2) && DeepEqual(differenceSetAB.values(), [ 'a', 'b' ])})());
```
</section>
## Challenge Seed
<section id='challengeSeed'>
<div id='js-seed'>
```js
class Set {
constructor() {
// This will hold the set
this.dictionary = {};
this.length = 0;
}
// this method will check for the presence of an element and return true or false
has(element) {
return this.dictionary[element] !== undefined;
}
// this method will return all the values in the set
values() {
return Object.keys(this.dictionary);
}
// this method will add an element to the set
add(element) {
if (!this.has(element)) {
this.dictionary[element] = true;
this.length++;
return true;
}
return false;
}
// this method will remove an element from a set
remove(element) {
if (this.has(element)) {
delete this.dictionary[element];
this.length--;
return true;
}
return false;
}
// this method will return the size of the set
size() {
return this.length;
}
// This is our union method from that lesson
union(set) {
const newSet = new Set();
this.values().forEach(value => {
newSet.add(value);
})
set.values().forEach(value => {
newSet.add(value);
})
return newSet;
}
// This is our intersection method from that lesson
intersection(set) {
const newSet = new Set();
let largeSet;
let smallSet;
if (this.dictionary.length > set.length) {
largeSet = this;
smallSet = set;
} else {
largeSet = set;
smallSet = this;
}
smallSet.values().forEach(value => {
if (largeSet.dictionary[value]) {
newSet.add(value);
}
})
return newSet;
}
// change code below this line
// change code above this line
}
```
</div>
</section>
## Solution
<section id='solution'>
```js
class Set {
constructor() {
this.dictionary = {};
this.length = 0;
}
has(element) {
return this.dictionary[element] !== undefined;
}
values() {
return Object.keys(this.dictionary);
}
add(element) {
if (!this.has(element)) {
this.dictionary[element] = true;
this.length++;
return true;
}
return false;
}
remove(element) {
if (this.has(element)) {
delete this.dictionary[element];
this.length--;
return true;
}
return false;
}
size() {
return this.length;
}
union(set) {
const newSet = new Set();
this.values().forEach(value => {
newSet.add(value);
})
set.values().forEach(value => {
newSet.add(value);
})
return newSet;
}
intersection(set) {
const newSet = new Set();
let largeSet;
let smallSet;
if (this.dictionary.length > set.length) {
largeSet = this;
smallSet = set;
} else {
largeSet = set;
smallSet = this;
}
smallSet.values().forEach(value => {
if (largeSet.dictionary[value]) {
newSet.add(value);
}
})
return newSet;
}
difference(set) {
const newSet = new Set();
this.values().forEach(value => {
if (!set.dictionary[value]) {
newSet.add(value);
}
})
return newSet;
}
}
```
</section>