freeCodeCamp/specify-only-the-lower-number-of-matches.english.md at a5818506f00d40d2b261ceaeb95f40fed3945373

SomeDer bfa5c26288 fix: use dfn instead of code tag (#36640 )

* Use dfn tags

* remove misused <dfn> tags

* Revert "remove misused <dfn> tags"

This reverts commit b24968a96810f618d831410ac90a0bc452ebde50.

* Update curriculum/challenges/english/01-responsive-web-design/basic-html-and-html5/fill-in-the-blank-with-placeholder-text.english.md

Co-Authored-By: Randell Dawson <5313213+RandellDawson@users.noreply.github.com>

* Make "array" lowercase

Co-Authored-By: Randell Dawson <5313213+RandellDawson@users.noreply.github.com>

* Fix dfn usage

* Address last dfn tags

2019-10-27 12:45:37 -04:00

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id, title, challengeType, forumTopicId

id	title	challengeType	forumTopicId
587d7db9367417b2b2512ba6	Specify Only the Lower Number of Matches	1	301366

Description

You can specify the lower and upper number of patterns with quantity specifiers using curly brackets. Sometimes you only want to specify the lower number of patterns with no upper limit. To only specify the lower number of patterns, keep the first number followed by a comma. For example, to match only the string "hah" with the letter a appearing at least 3 times, your regex would be /ha{3,}h/.

let A4 = "haaaah";
let A2 = "haah";
let A100 = "h" + "a".repeat(100) + "h";
let multipleA = /ha{3,}h/;
multipleA.test(A4); // Returns true
multipleA.test(A2); // Returns false
multipleA.test(A100); // Returns true

Instructions

Change the regex haRegex to match the word "Hazzah" only when it has four or more letter z's.

Tests

tests:
  - text: Your regex should use curly brackets.
    testString: assert(haRegex.source.match(/{.*?}/).length > 0);
  - text: Your regex should not match <code>"Hazzah"</code>
    testString: assert(!haRegex.test("Hazzah"));
  - text: Your regex should not match <code>"Hazzzah"</code>
    testString: assert(!haRegex.test("Hazzzah"));
  - text: Your regex should match <code>"Hazzzzah"</code>
    testString: assert("Hazzzzah".match(haRegex)[0].length === 8);
  - text: Your regex should match <code>"Hazzzzzah"</code>
    testString: assert("Hazzzzzah".match(haRegex)[0].length === 9);
  - text: Your regex should match <code>"Hazzzzzzah"</code>
    testString: assert("Hazzzzzzah".match(haRegex)[0].length === 10);
  - text: Your regex should match <code>"Hazzah"</code> with 30 <code>z</code>'s in it.
    testString: assert("Hazzzzzzzzzzzzzzzzzzzzzzzzzzzzzzah".match(haRegex)[0].length === 34);

Challenge Seed

let haStr = "Hazzzzah";
let haRegex = /change/; // Change this line
let result = haRegex.test(haStr);

Solution

let haStr = "Hazzzzah";
let haRegex = /Haz{4,}ah/; // Change this line
let result = haRegex.test(haStr);

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