* feat(tools): add seed/solution restore script * chore(curriculum): remove empty sections' markers * chore(curriculum): add seed + solution to Chinese * chore: remove old formatter * fix: update getChallenges parse translated challenges separately, without reference to the source * chore(curriculum): add dashedName to English * chore(curriculum): add dashedName to Chinese * refactor: remove unused challenge property 'name' * fix: relax dashedName requirement * fix: stray tag Remove stray `pre` tag from challenge file. Signed-off-by: nhcarrigan <nhcarrigan@gmail.com> Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
53 lines
1.1 KiB
Markdown
53 lines
1.1 KiB
Markdown
---
|
|
id: 5900f3b41000cf542c50fec7
|
|
title: 'Problem 72: Counting fractions'
|
|
challengeType: 5
|
|
forumTopicId: 302185
|
|
dashedName: problem-72-counting-fractions
|
|
---
|
|
|
|
# --description--
|
|
|
|
Consider the fraction, `n`/`d`, where n and d are positive integers. If `n`<`d` and HCF(`n`,`d`)=1, it is called a reduced proper fraction.
|
|
|
|
If we list the set of reduced proper fractions for `d` ≤ 8 in ascending order of size, we get:
|
|
|
|
<div style='text-align: center;'>1/8, 1/7, 1/6, 1/5, 1/4, 2/7, 1/3, 3/8, 2/5, 3/7, 1/2, 4/7, 3/5, 5/8, 2/3, 5/7, 3/4, 4/5, 5/6, 6/7, 7/8</div>
|
|
|
|
It can be seen that there are 21 elements in this set.
|
|
|
|
How many elements would be contained in the set of reduced proper fractions for `d` ≤ 1,000,000?
|
|
|
|
# --hints--
|
|
|
|
`countingFractions()` should return a number.
|
|
|
|
```js
|
|
assert(typeof countingFractions() === 'number');
|
|
```
|
|
|
|
`countingFractions()` should return 303963552391.
|
|
|
|
```js
|
|
assert.strictEqual(countingFractions(), 303963552391);
|
|
```
|
|
|
|
# --seed--
|
|
|
|
## --seed-contents--
|
|
|
|
```js
|
|
function countingFractions() {
|
|
|
|
return true;
|
|
}
|
|
|
|
countingFractions();
|
|
```
|
|
|
|
# --solutions--
|
|
|
|
```js
|
|
// solution required
|
|
```
|