2.3 KiB
2.3 KiB
id, title, challengeType, forumTopicId
id | title | challengeType | forumTopicId |
---|---|---|---|
587d7db9367417b2b2512ba6 | Specify Only the Lower Number of Matches | 1 | 301366 |
Description
"hah"
with the letter a
appearing at least 3
times, your regex would be /ha{3,}h/
.
let A4 = "haaaah";
let A2 = "haah";
let A100 = "h" + "a".repeat(100) + "h";
let multipleA = /ha{3,}h/;
multipleA.test(A4); // Returns true
multipleA.test(A2); // Returns false
multipleA.test(A100); // Returns true
Instructions
haRegex
to match the word "Hazzah"
only when it has four or more letter z
's.
Tests
tests:
- text: Your regex should use curly brackets.
testString: assert(haRegex.source.match(/{.*?}/).length > 0);
- text: Your regex should not match <code>"Hazzah"</code>
testString: assert(!haRegex.test("Hazzah"));
- text: Your regex should not match <code>"Hazzzah"</code>
testString: assert(!haRegex.test("Hazzzah"));
- text: Your regex should match <code>"Hazzzzah"</code>
testString: assert("Hazzzzah".match(haRegex)[0].length === 8);
- text: Your regex should match <code>"Hazzzzzah"</code>
testString: assert("Hazzzzzah".match(haRegex)[0].length === 9);
- text: Your regex should match <code>"Hazzzzzzah"</code>
testString: assert("Hazzzzzzah".match(haRegex)[0].length === 10);
- text: Your regex should match <code>"Hazzah"</code> with 30 <code>z</code>'s in it.
testString: assert("Hazzzzzzzzzzzzzzzzzzzzzzzzzzzzzzah".match(haRegex)[0].length === 34);
Challenge Seed
let haStr = "Hazzzzah";
let haRegex = /change/; // Change this line
let result = haRegex.test(haStr);
Solution
let haStr = "Hazzzzah";
let haRegex = /Haz{4,}ah/; // Change this line
let result = haRegex.test(haStr);