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freeCodeCamp/curriculum/challenges/english/10-coding-interview-prep/project-euler/problem-61-cyclical-figurate-numbers.md
Oliver Eyton-Williams ee1e8abd87 feat(curriculum): restore seed + solution to Chinese (#40683)
* feat(tools): add seed/solution restore script

* chore(curriculum): remove empty sections' markers

* chore(curriculum): add seed + solution to Chinese

* chore: remove old formatter

* fix: update getChallenges

parse translated challenges separately, without reference to the source

* chore(curriculum): add dashedName to English

* chore(curriculum): add dashedName to Chinese

* refactor: remove unused challenge property 'name'

* fix: relax dashedName requirement

* fix: stray tag

Remove stray `pre` tag from challenge file.

Signed-off-by: nhcarrigan <nhcarrigan@gmail.com>

Co-authored-by: nhcarrigan <nhcarrigan@gmail.com>
2021-01-12 19:31:00 -07:00

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---
id: 5900f3a91000cf542c50febc
title: 'Problem 61: Cyclical figurate numbers'
challengeType: 5
forumTopicId: 302173
dashedName: problem-61-cyclical-figurate-numbers
---
# --description--
Triangle, square, pentagonal, hexagonal, heptagonal, and octagonal numbers are all figurate (polygonal) numbers and are generated by the following formulae:
| Type of Number | Formula | Sequence |
| -------------- | --------------------------------------------------------------------- | --------------------- |
| Triangle | P<sub>3</sub>,<var><sub>n</sub></var>=<var>n</var>(<var>n</var>+1)/2 | 1, 3, 6, 10, 15, ... |
| Square | P<sub>4</sub>,<var><sub>n</sub></var>=<var>n</var><sup>2</sup> | 1, 4, 9, 16, 25, ... |
| Pentagonal | P<sub>5</sub>,<var><sub>n</sub></var>=<var>n</var>(3<var>n</var>1)/2 | 1, 5, 12, 22, 35, ... |
| Hexagonal | P<sub>6</sub>,<var><sub>n</sub></var>=<var>n</var>(2<var>n</var>1) | 1, 6, 15, 28, 45, ... |
| Heptagonal | P<sub>7</sub>,<var><sub>n</sub></var>=<var>n</var>(5<var>n</var>3)/2 | 1, 7, 18, 34, 55, ... |
| Octagonal | P<sub>8</sub>,<var><sub>n</sub></var>=<var>n</var>(3<var>n</var>2) | 1, 8, 21, 40, 65, ... |
The ordered set of three 4-digit numbers: 8128, 2882, 8281, has three interesting properties.
<ol>
<li>The set is cyclic, in that the last two digits of each number is the first two digits of the next number (including the last number with the first).</li>
<li>Each polygonal type: triangle (P<sub>3,127</sub> = 8128), square (P<sub>4,91</sub> = 8281), and pentagonal (P<sub>5,44</sub> = 2882), is represented by a different number in the set.</li>
<li>This is the only set of 4-digit numbers with this property.</li>
</ol>
Find the sum of the only ordered set of six cyclic 4-digit numbers for which each polygonal type: triangle, square, pentagonal, hexagonal, heptagonal, and octagonal, is represented by a different number in the set.
# --hints--
`cyclicalFigurateNums()` should return a number.
```js
assert(typeof cyclicalFigurateNums() === 'number');
```
`cyclicalFigurateNums()` should return 28684.
```js
assert.strictEqual(cyclicalFigurateNums(), 28684);
```
# --seed--
## --seed-contents--
```js
function cyclicalFigurateNums() {
return true;
}
cyclicalFigurateNums();
```
# --solutions--
```js
// solution required
```