1.2 KiB
1.2 KiB
id, title, challengeType, forumTopicId, dashedName
| id | title | challengeType | forumTopicId | dashedName |
|---|---|---|---|---|
| 5900f5151000cf542c510028 | Problem 425: Prime connection | 5 | 302095 | problem-425-prime-connection |
--description--
Two positive numbers A and B are said to be connected (denoted by "$A ↔ B$") if one of these conditions holds:
AandBhave the same length and differ in exactly one digit; for example,123 ↔ 173.- Adding one digit to the left of
A(orB) makesB(orA); for example,23 ↔ 223and123 ↔ 23.
We call a prime P a 2's relative if there exists a chain of connected primes between 2 and P and no prime in the chain exceeds P.
For example, 127 is a 2's relative. One of the possible chains is shown below:
2 ↔ 3 ↔ 13 ↔ 113 ↔ 103 ↔ 107 ↔ 127
However, 11 and 103 are not 2's relatives.
Let F(N) be the sum of the primes ≤ N which are not 2's relatives. We can verify that F({10}^3) = 431 and F({10}^4) = 78\\,728.
Find F({10}^7).
--hints--
primeConnection() should return 46479497324.
assert.strictEqual(primeConnection(), 46479497324);
--seed--
--seed-contents--
function primeConnection() {
return true;
}
primeConnection();
--solutions--
// solution required