freeCodeCamp/curriculum/challenges/chinese/10-coding-interview-prep/project-euler/problem-1-multiples-of-3-and-5.md

id, title, challengeType, forumTopicId, dashedName

id	title	challengeType	forumTopicId	dashedName
5900f36e1000cf542c50fe80	Problem 1: Multiples of 3 and 5	5	301722	problem-1-multiples-of-3-and-5

--description--

If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.

Find the sum of all the multiples of 3 or 5 below the provided parameter value number.

--hints--

multiplesOf3and5(10) should return a number.

assert(typeof multiplesOf3and5(10) === 'number');

multiplesOf3and5(49) should return 543.

assert.strictEqual(multiplesOf3and5(49), 543);

multiplesOf3and5(1000) should return 233168.

assert.strictEqual(multiplesOf3and5(1000), 233168);

multiplesOf3and5(8456) should return 16687353.

assert.strictEqual(multiplesOf3and5(8456), 16687353);

multiplesOf3and5(19564) should return 89301183.

assert.strictEqual(multiplesOf3and5(19564), 89301183);

--seed--

--seed-contents--

function multiplesOf3and5(number) {

  return true;
}

multiplesOf3and5(1000);

--solutions--

const multiplesOf3and5 = (number) => {
  var total = 0;

  for(var i = 0; i < number; i++) {
    if(i % 3 == 0 || i % 5 == 0) {
      total += i;
    }
  }
  return total;
};