57 lines
		
	
	
		
			1.3 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
			
		
		
	
	
			57 lines
		
	
	
		
			1.3 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
| ---
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| id: 5900f4531000cf542c50ff65
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| title: 'Problem 230: Fibonacci Words'
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| challengeType: 5
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| forumTopicId: 301874
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| dashedName: problem-230-fibonacci-words
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| ---
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| 
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| # --description--
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| 
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| For any two strings of digits, A and B, we define FA,B to be the sequence (A,B,AB,BAB,ABBAB,...) in which each term is the concatenation of the previous two.
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| 
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| Further, we define DA,B(n) to be the nth digit in the first term of FA,B that contains at least n digits.
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| 
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| Example:
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| 
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| Let A=1415926535, B=8979323846. We wish to find DA,B(35), say.
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| 
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| The first few terms of FA,B are: 1415926535 8979323846 14159265358979323846 897932384614159265358979323846 14159265358979323846897932384614159265358979323846
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| 
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| Then DA,B(35) is the 35th digit in the fifth term, which is 9.
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| 
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| Now we use for A the first 100 digits of π behind the decimal point: 14159265358979323846264338327950288419716939937510 58209749445923078164062862089986280348253421170679
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| 
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| and for B the next hundred digits:
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| 
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| 82148086513282306647093844609550582231725359408128 48111745028410270193852110555964462294895493038196 .
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| 
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| Find ∑n = 0,1,...,17 10n× DA,B((127+19n)×7n) .
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| 
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| # --hints--
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| 
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| `euler230()` should return 850481152593119200.
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| 
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| ```js
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| assert.strictEqual(euler230(), 850481152593119200);
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| ```
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| 
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| # --seed--
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| 
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| ## --seed-contents--
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| 
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| ```js
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| function euler230() {
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| 
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|   return true;
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| }
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| 
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| euler230();
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| ```
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| 
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| # --solutions--
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| 
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| ```js
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| // solution required
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| ```
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