84 lines
		
	
	
		
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			Markdown
		
	
	
	
	
	
			
		
		
	
	
			84 lines
		
	
	
		
			1.9 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
| ---
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| id: 5900f3881000cf542c50fe9b
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| title: 'Problem 28: Number spiral diagonals'
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| challengeType: 5
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| forumTopicId: 301930
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| dashedName: problem-28-number-spiral-diagonals
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| ---
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| 
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| # --description--
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| 
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| Starting with the number 1 and moving to the right in a clockwise direction a 5 by 5 spiral is formed as follows:
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| 
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| <div style='padding-left: 4em;'>
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|   <div style='color: red; display: inline;'>21</div> 22 23 24 <div style='color: red; display: inline;'>25</div><br>
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|   20  <div style='color: red; display: inline;'>7</div>  8  <div style='color: red; display: inline;'>9</div> 10<br>
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|   19  6  <div style='color: red; display: inline;'>1</div>  2 11<br>
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|   18  <div style='color: red; display: inline;'>5</div>  4  <div style='color: red; display: inline;'>3</div> 12<br>
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|   <div style='color: red; display: inline;'>17</div> 16 15 14 <div style='color: red; display: inline;'>13</div><br>
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| </div>
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| 
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| It can be verified that the sum of the numbers on the diagonals is 101.
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| 
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| What is the sum of the numbers on the diagonals in an `n` by `n` spiral formed in the same way?
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| 
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| # --hints--
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| 
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| `spiralDiagonals(101)` should return a number.
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| 
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| ```js
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| assert(typeof spiralDiagonals(101) === 'number');
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| ```
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| 
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| `spiralDiagonals(101)` should return 692101.
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| 
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| ```js
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| assert(spiralDiagonals(101) == 692101);
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| ```
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| 
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| `spiralDiagonals(303)` should return 18591725.
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| 
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| ```js
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| assert(spiralDiagonals(303) == 18591725);
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| ```
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| 
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| `spiralDiagonals(505)` should return 85986601.
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| 
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| ```js
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| assert(spiralDiagonals(505) == 85986601);
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| ```
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| 
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| `spiralDiagonals(1001)` should return 669171001.
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| 
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| ```js
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| assert(spiralDiagonals(1001) == 669171001);
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| ```
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| 
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| # --seed--
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| 
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| ## --seed-contents--
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| 
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| ```js
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| function spiralDiagonals(n) {
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| 
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|   return n;
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| }
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| 
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| spiralDiagonals(1001);
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| ```
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| 
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| # --solutions--
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| 
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| ```js
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| const spiralDiagonals = (n) => {
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|   const Sn2 = (n) => {
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|     return n*(n+1)*(2*n+1)/6;
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|   };
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|   const Sn = (n) => {
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|     return n*(n+1)/2;
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|   };
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|   let sum = (Sn2(n-1) + Sn(n-1) + n-1) + (Math.floor(n/2) + Sn2(n));
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|   return sum;
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| };
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| ```
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