51 lines
		
	
	
		
			1.4 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
			
		
		
	
	
			51 lines
		
	
	
		
			1.4 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
| ---
 | |
| id: 5900f4b91000cf542c50ffcc
 | |
| title: 'Problem 333: Special partitions'
 | |
| challengeType: 5
 | |
| forumTopicId: 301991
 | |
| dashedName: problem-333-special-partitions
 | |
| ---
 | |
| 
 | |
| # --description--
 | |
| 
 | |
| All positive integers can be partitioned in such a way that each and every term of the partition can be expressed as 2ix3j, where i,j ≥ 0.
 | |
| 
 | |
| Let's consider only those such partitions where none of the terms can divide any of the other terms. For example, the partition of 17 = 2 + 6 + 9 = (21x30 + 21x31 + 20x32) would not be valid since 2 can divide 6. Neither would the partition 17 = 16 + 1 = (24x30 + 20x30) since 1 can divide 16. The only valid partition of 17 would be 8 + 9 = (23x30 + 20x32).
 | |
| 
 | |
| Many integers have more than one valid partition, the first being 11 having the following two partitions. 11 = 2 + 9 = (21x30 + 20x32) 11 = 8 + 3 = (23x30 + 20x31)
 | |
| 
 | |
| Let's define P(n) as the number of valid partitions of n. For example, P(11) = 2.
 | |
| 
 | |
| Let's consider only the prime integers q which would have a single valid partition such as P(17).
 | |
| 
 | |
| The sum of the primes q <100 such that P(q)=1 equals 233.
 | |
| 
 | |
| Find the sum of the primes q <1000000 such that P(q)=1.
 | |
| 
 | |
| # --hints--
 | |
| 
 | |
| `euler333()` should return 3053105.
 | |
| 
 | |
| ```js
 | |
| assert.strictEqual(euler333(), 3053105);
 | |
| ```
 | |
| 
 | |
| # --seed--
 | |
| 
 | |
| ## --seed-contents--
 | |
| 
 | |
| ```js
 | |
| function euler333() {
 | |
| 
 | |
|   return true;
 | |
| }
 | |
| 
 | |
| euler333();
 | |
| ```
 | |
| 
 | |
| # --solutions--
 | |
| 
 | |
| ```js
 | |
| // solution required
 | |
| ```
 |