61460c8601
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57 lines
1.0 KiB
Markdown
57 lines
1.0 KiB
Markdown
---
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id: 5900f52c1000cf542c51003f
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challengeType: 5
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title: 'Problem 448: Average least common multiple'
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videoUrl: ''
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localeTitle: 问题448：平均最小公倍数
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---
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## Description
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<section id="description">函数lcm（a，b）表示a和b的最小公倍数。设A（n）为1≤i≤n的lcm（n，i）的平均值。例如：A（2）=（2 + 2）/ 2 = 2且A（10）=（10 + 10 + 30 + 20 + 10 + 30 + 70 + 40 + 90 + 10）/ 10 = 32。 <p>令S（n）=ΣA（k）为1≤k≤n。 S（100）= 122726。 </p><p>找到S（99999999019）mod 999999017。 </p></section>
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## Instructions
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<section id="instructions">
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</section>
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## Tests
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<section id='tests'>
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```yml
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tests:
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- text: <code>euler448()</code>应该返回106467648。
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testString: assert.strictEqual(euler448(), 106467648);
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```
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</section>
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## Challenge Seed
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<section id='challengeSeed'>
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<div id='js-seed'>
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```js
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function euler448() {
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// Good luck!
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return true;
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}
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euler448();
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```
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</div>
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</section>
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## Solution
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<section id='solution'>
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```js
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// solution required
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```
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/section>
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