61460c8601
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61 lines
1.4 KiB
Markdown
61 lines
1.4 KiB
Markdown
---
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id: 5900f3721000cf542c50fe85
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challengeType: 5
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title: 'Problem 6: Sum square difference'
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videoUrl: ''
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localeTitle: 问题6：求和方差
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---
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## Description
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<section id="description">前十个自然数的平方和是， <div style="text-align: center;"> 1 <sup>2</sup> + 2 <sup>2</sup> + ... + 10 <sup>2</sup> = 385 </div>前十个自然数之和的平方是， <div style="text-align: center;"> （1 + 2 + ... + 10） <sup>2</sup> = 55 <sup>2</sup> = 3025 </div>因此，前十个自然数的平方和与和的平方之间的差值为3025 - 385 = 2640.求出前<code>n</code>自然数的平方和与总和的平方之间的差值。 </section>
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## Instructions
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<section id="instructions">
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</section>
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## Tests
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<section id='tests'>
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```yml
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tests:
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- text: <code>sumSquareDifference(10)</code>应该返回2640。
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testString: assert.strictEqual(sumSquareDifference(10), 2640);
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- text: <code>sumSquareDifference(20)</code>应该返回41230。
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testString: assert.strictEqual(sumSquareDifference(20), 41230);
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- text: <code>sumSquareDifference(100)</code>应该返回25164150。
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testString: assert.strictEqual(sumSquareDifference(100), 25164150);
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```
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</section>
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## Challenge Seed
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<section id='challengeSeed'>
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<div id='js-seed'>
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```js
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function sumSquareDifference(n) {
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// Good luck!
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return true;
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}
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sumSquareDifference(100);
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```
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</div>
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</section>
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## Solution
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<section id='solution'>
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```js
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// solution required
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```
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/section>
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