freeCodeCamp/compound-assignment-with-augmented-division.english.md at c2bbde95a314df738be94e462e3b21930d2c84e4

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Randell Dawson 3ec1fe8ea7 feat: add forumTopicId to challenge frontmatter [pre-existing]

This commit adds the pre-existing challenge guide topics in the
forum to the forntmatter of their challenge markdown files.

2019-08-05 22:14:37 +05:30

1.6 KiB

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id, title, challengeType, videoUrl, forumTopicId

id	title	challengeType	videoUrl	forumTopicId
56533eb9ac21ba0edf2244b2	Compound Assignment With Augmented Division	1	https://scrimba.com/c/c2QvKT2	16659

Description

The /= operator divides a variable by another number. myVar = myVar / 5; Will divide myVar by 5. This can be rewritten as: myVar /= 5;

Instructions

Convert the assignments for a, b, and c to use the /= operator.

Tests

tests:
  - text: <code>a</code> should equal <code>4</code>
    testString: assert(a === 4);
  - text: <code>b</code> should equal <code>27</code>
    testString: assert(b === 27);
  - text: <code>c</code> should equal <code>3</code>
    testString: assert(c === 3);
  - text: You should use the <code>/=</code> operator for each variable
    testString: assert(code.match(/\/=/g).length === 3);
  - text: Do not modify the code above the line
    testString: assert(/var a = 48;/.test(code) && /var b = 108;/.test(code) && /var c = 33;/.test(code));

Challenge Seed

var a = 48;
var b = 108;
var c = 33;

// Only modify code below this line

a = a / 12;
b = b / 4;
c = c / 11;

After Test

(function(a,b,c){ return "a = " + a + ", b = " + b + ", c = " + c; })(a,b,c);

Solution

var a = 48;
var b = 108;
var c = 33;

a /= 12;
b /= 4;
c /= 11;

1.6 KiB Raw Blame History