Files
freeCodeCamp/curriculum/challenges/english/08-coding-interview-prep/project-euler/problem-48-self-powers.english.md
Kristofer Koishigawa 6cfd0fc503 fix: improve Project Euler descriptions, challenge seeds, and test cases (#38016)
* fix: improve Project Euler descriptions and test case

Improve formatting of Project Euler test descriptions. Also add poker hands array and new test case for problem 54

* feat: add typeof tests and gave functions proper names for first 100 challenges

* fix: continue fixing test descriptions and adding "before test" sections

* fix: address review comments

* fix: adjust grids in 18 and 67 and fix some text that reference files rather than the given arrays

* fix: implement bug fixes and improvements from review

* fix: remove console.log statements from seed and solution
2020-02-28 06:39:47 -06:00

1.7 KiB

id, challengeType, title, forumTopicId
id challengeType title forumTopicId
5900f39c1000cf542c50feaf 5 Problem 48: Self powers 302157

Description

The series, 11 + 22 + 33 + ... + 1010 = 10405071317.

Find the last ten digits of the series, 11 + 22 + 33 + ... + 10001000.

Instructions

Tests

tests:
  - text: <code>selfPowers(10, 3)</code> should return a number.
    testString: assert(typeof selfPowers(10, 3) === 'number');
  - text: <code>selfPowers(10, 3)</code> should return 317.
    testString: assert.strictEqual(selfPowers(10, 3), 317);
  - text: <code>selfPowers(150, 6)</code> should return 29045.
    testString: assert.strictEqual(selfPowers(150, 6), 29045);
  - text: <code>selfPowers(673, 7)</code> should return 2473989.
    testString: assert.strictEqual(selfPowers(673, 7), 2473989);
  - text: <code>selfPowers(1000, 10)</code> should return 9110846700.
    testString: assert.strictEqual(selfPowers(1000, 10), 9110846700);

Challenge Seed

function selfPowers(power, lastDigits) {
  // Good luck!
  return true;
}

selfPowers(1000, 10);

Solution

function selfPowers(power, lastDigits) {
  let sum = 0;
  const modulo = Math.pow(10, lastDigits);

  for (let i = 1; i <= power; i++) {
    let temp = i;
    for (let j = 1; j < i; j++) {
      temp *= i;
      temp %= modulo;
    }

    sum += temp;
    sum %= modulo;
  }

  return sum;
}