68 lines
1.6 KiB
Markdown
68 lines
1.6 KiB
Markdown
---
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id: 5966f99c45e8976909a85575
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challengeType: 5
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videoUrl: ''
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title: 一周中的天
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---
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## Description
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<section id="description"><p>一家公司决定，每当圣诞节落在星期天，他们将给予他们的工人所有额外带薪假期，这样，在任何公共假期，工人将不必在下一周（12月25日到1月1日之间）工作。 </p><p>任务： </p><p>编写一个开始年份和结束年份的函数，并返回12月25日为星期日的所有年份的数组。 </p></section>
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## Instructions
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<section id="instructions">
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</section>
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## Tests
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<section id='tests'>
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```yml
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tests:
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- text: <code>findXmasSunday</code>是一个函数。
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testString: assert(typeof findXmasSunday === 'function');
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- text: '<code>findChristmasSunday(2000, 2100)</code>应该返回一个数组。'
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testString: assert(typeof findXmasSunday(2000, 2100) === 'object');
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- text: '<code>findChristmasSunday(2008, 2121</code>应该回归[1977,1983,1988,1994,2005,2011,2016]'
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testString: assert.deepEqual(findXmasSunday(1970, 2017), firstSolution);
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- text: '<code>findChristmasSunday(2008, 2121</code>应该返回[2011,2016,2022,2033,2039,2044,2050,2061,2067,2072,2078,2089,2095,2101,2107,2112,2118]'
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testString: assert.deepEqual(findXmasSunday(2008, 2121), secondSolution);
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```
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</section>
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## Challenge Seed
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<section id='challengeSeed'>
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<div id='js-seed'>
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```js
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function findXmasSunday (start, end) {
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// Good luck!
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return true;
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}
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```
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</div>
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### After Test
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<div id='js-teardown'>
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```js
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console.info('after the test');
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```
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</div>
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</section>
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## Solution
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<section id='solution'>
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```js
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// solution required
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```
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/section>
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