75 lines
		
	
	
		
			2.9 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
			
		
		
	
	
			75 lines
		
	
	
		
			2.9 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
| ---
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| id: 587d8259367417b2b2512c83
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| title: Invert a Binary Tree
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| challengeType: 1
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| videoUrl: ''
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| localeTitle: 反转二叉树
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| ---
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| 
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| ## Description
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| <section id="description">这里我们将创建一个反转二叉树的函数。给定二叉树,我们希望生成一个新树,它等效于该树的镜像。与原始树的inorder遍历相比,在倒置树上运行inorder遍历将以相反的顺序探索节点。在我们的二叉树上编写一个名为<code>invert</code>的方法。调用此方法应该反转当前树结构。理想情况下,我们希望在线性时间内就地执行此操作。也就是说,我们只访问每个节点一次,我们在不使用任何额外内存的情况下修改现有的树结构。祝你好运! </section>
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| 
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| ## Instructions
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| <section id="instructions">
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| </section>
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| 
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| ## Tests
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| <section id='tests'>
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| 
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| ```yml
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| tests:
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|   - text: 存在<code>BinarySearchTree</code>数据结构。
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|     testString: 'assert((function() { var test = false; if (typeof BinarySearchTree !== "undefined") { test = new BinarySearchTree() }; return (typeof test == "object")})(), "The <code>BinarySearchTree</code> data structure exists.");'
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|   - text: 二叉搜索树有一个名为<code>invert</code>的方法。
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|     testString: 'assert((function() { var test = false; if (typeof BinarySearchTree !== "undefined") { test = new BinarySearchTree() } else { return false; }; return (typeof test.invert == "function")})(), "The binary search tree has a method called <code>invert</code>.");'
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|   - text: <code>invert</code>方法正确地反转树结构。
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|     testString: 'assert((function() { var test = false; if (typeof BinarySearchTree !== "undefined") { test = new BinarySearchTree() } else { return false; }; if (typeof test.invert !== "function") { return false; }; test.add(4); test.add(1); test.add(7); test.add(87); test.add(34); test.add(45); test.add(73); test.add(8); test.invert(); return test.inorder().join("") == "877345348741"; })(), "The <code>invert</code> method correctly inverts the tree structure.");'
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|   - text: 反转空树返回<code>null</code> 。
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|     testString: 'assert((function() { var test = false; if (typeof BinarySearchTree !== "undefined") { test = new BinarySearchTree() } else { return false; }; if (typeof test.invert !== "function") { return false; }; return (test.invert() == null); })(), "Inverting an empty tree returns <code>null</code>.");'
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| 
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| ```
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| 
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| </section>
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| 
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| ## Challenge Seed
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| <section id='challengeSeed'>
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| 
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| <div id='js-seed'>
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| 
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| ```js
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| var displayTree = (tree) => console.log(JSON.stringify(tree, null, 2));
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| function Node(value) {
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|     this.value = value;
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|     this.left = null;
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|     this.right = null;
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| }
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| function BinarySearchTree() {
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|     this.root = null;
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|     // change code below this line
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|     // change code above this line
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| }
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| 
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| ```
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| 
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| </div>
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| 
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| 
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| ### After Test
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| <div id='js-teardown'>
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| 
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| ```js
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| console.info('after the test');
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| ```
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| 
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| </div>
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| 
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| </section>
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| 
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| ## Solution
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| <section id='solution'>
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| 
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| ```js
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| // solution required
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| ```
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| </section>
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