55 lines
		
	
	
		
			1.4 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
			
		
		
	
	
			55 lines
		
	
	
		
			1.4 KiB
		
	
	
	
		
			Markdown
		
	
	
	
	
	
| ---
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| id: 5900f4f11000cf542c510003
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| title: 'Problem 387: Harshad Numbers'
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| challengeType: 5
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| forumTopicId: 302051
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| dashedName: problem-387-harshad-numbers
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| ---
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| 
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| # --description--
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| 
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| A Harshad or Niven number is a number that is divisible by the sum of its digits.
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| 
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| 201 is a Harshad number because it is divisible by 3 (the sum of its digits.)
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| 
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| When we truncate the last digit from 201, we get 20, which is a Harshad number.
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| 
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| When we truncate the last digit from 20, we get 2, which is also a Harshad number.
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| 
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| Let's call a Harshad number that, while recursively truncating the last digit, always results in a Harshad number a right truncatable Harshad number.
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| 
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| Also: 201/3=67 which is prime. Let's call a Harshad number that, when divided by the sum of its digits, results in a prime a strong Harshad number.
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| 
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| Now take the number 2011 which is prime. When we truncate the last digit from it we get 201, a strong Harshad number that is also right truncatable. Let's call such primes strong, right truncatable Harshad primes.
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| 
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| You are given that the sum of the strong, right truncatable Harshad primes less than 10000 is 90619.
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| 
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| Find the sum of the strong, right truncatable Harshad primes less than 1014.
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| 
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| # --hints--
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| 
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| `euler387()` should return 696067597313468.
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| 
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| ```js
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| assert.strictEqual(euler387(), 696067597313468);
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| ```
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| 
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| # --seed--
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| 
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| ## --seed-contents--
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| 
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| ```js
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| function euler387() {
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| 
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|   return true;
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| }
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| 
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| euler387();
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| ```
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| 
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| # --solutions--
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| 
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| ```js
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| // solution required
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| ```
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